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KatRina [158]
2 years ago
10

Convert: 15 days into seconds​

Mathematics
2 answers:
tankabanditka [31]2 years ago
8 0

Answer:

1296000 seconds

Step-by-step explanation:

Hope this helps

NNADVOKAT [17]2 years ago
7 0
Explanation:
1min=60secs
1hour= 60mins= 60x60= 3,600secs
1day= 24hrs= 3600x24= 86,400secs
Therefore, 15days= 86,400x15= 1,296,000secs

Answer: 15 days= 1,296,000 seconds

Hope it helps u! :)
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How many eights make a half
evablogger [386]

Answer:

Four, because 4/8 = 1/2 There are obviously 8 1/8ths in a whole so half of that amount is obviously 4 1/8ths.

Step-by-step explanation:

Gave above.

7 0
3 years ago
Jamal has at most $100 to spend on computer paper and printer ink for his computer. He buys 1 box of paper for $24.99. If ink ca
lions [1.4K]

Answer:

1 box of paper with 3 ink cartridges

Step-by-step explanation:

$100 total

$24.99+19.99(3)= $84.96 (4 ink cartridges would be over the allotted amount)

7 0
3 years ago
Rex spent $6.42 at the store. He gave the cashier the money shown above. How much money did Rex get back from the cashier?
cupoosta [38]
The answer is d 10-6.42 is $3.58
4 0
3 years ago
Read 2 more answers
The sum of two positive integers, a and b, is at least 30. The difference of the two integers is at least 10. If b is th
Dafna11 [192]

Answer:

a + b \geq 30

b - a \geq 10

Step-by-step explanation:

Given

The sum of the two positive integer a and b is at least 30, this means the sum of the two positive integer is 30 or greater than 30, so we write the inequalities as below.

a + b \geq 30

The difference of the two integers is at least 10, if b is the greater integer then we subtract integer a from integer b, so we write the inequality as below.

b - a \geq 10

Therefore, the following system of inequalities could represent the values of two positive integers a and b.

a + b \geq 30

b - a \geq 10

6 0
3 years ago
How many solutions does the equation |x + 6| − 4 = c have if c = 5? If c = −10? Complete the explanation
mixer [17]

Answer:

<h2>For c = 5 → two solutions</h2><h2>For c = -10 → no solutions</h2>

Step-by-step explanation:

We know

|a|\geq0

for any real value of <em>a</em>.

|a| = b > 0 -  <em>two solutions: </em>a = b or a = -b

|a| = 0 - <em>one solution: a = 0</em>

|a| = b < 0 - <em>no solution</em>

<em />

|x + 6| - 4 = c

for c = 5:

|x + 6| - 4 = 5           <em>add 4 to both sides</em>

|x + 6| = 9 > 0   <em>TWO SOLUTIONS</em>

for c = -10

|x + 6| - 4 = -10           <em>add 4 to both sides</em>

|x + 6| = -6 < 0   <em>NO SOLUTIONS</em>

<em></em>

Calculate the solutions for c = 5:

|x + 6| = 9 ⇔ x + 6 = 9 or x + 6 = -9         <em>subtract 6 from both sides</em>

x = 3 or x = -15

5 0
3 years ago
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