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joja [24]
3 years ago
7

Please help me on this equation 9x-71>3(3x-7u)

Mathematics
2 answers:
kakasveta [241]3 years ago
7 0
<span>9x-71>3(3x-7u)
</span>⇒ 9x -71 > 3*3x -3*7u (distributive property)
⇒ 9x -71 > 9x -21u
⇒ (9x -9x) -71 > (9x -9x) -21u
⇒ -71 > -21u
⇒ -21u < -71
⇒ u > -71/(-21)
⇒ u > 3 8/21
<span>
Final answer: </span>u > 3 8/21~
777dan777 [17]3 years ago
3 0
9x - 71 > 3(3x - 7u)
Expand the brackets
9x - 71 > 9x -21u
Subtract 9x from both sides
-71 > -21u
multiply by -1 to make positive
71 > 21u
Divide both sides by 21 to get what u equals
71/21 = 3.3....
U must be more than 71/21 or 3.3

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3 years ago
Solving system of equations by substitution
weeeeeb [17]
Y=3x-10 and 3x+2y=16
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3x+2y=16
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3 years ago
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4 0
3 years ago
Factorise : x^2+x-72 Step by Step​
Ivan

Answer:

(x + 9)(x - 8)

Step-by-step explanation:

f(x) = x^2 + x - 72

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4 0
3 years ago
Read 2 more answers
Write each fraction as a sum or difference 14-6x/19
Oksanka [162]
<span>Given number : 14 - 6x / 19
So we need to write this fraction as a sum or difference.
First, simplify the given number:
=> 14 – 6x / 19
=> <u>14 x 19 – (6x</u>)
            19
=> <u>266 – 6x</u>
         19
=> 266 – 6x = -2 * (3x - 133)
Thus, the final result would be:
=> <u>-2 * (3x - 133) </u> => This will be the fraction sum or difference of the given number<u>
</u>               19

</span>



8 0
3 years ago
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