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VashaNatasha [74]
3 years ago
15

You and your bicycle have combined mass 80.0 kg. When you reach the base of a bridge, you are travelling along the road at 7.50

m/s. At the top of the bridge, you have climbed a vertical distance of 5.20 m and have slowed to 3.00 m/s. Ignore work done by friction and any inefficiency in the bike or your legs.
Part A
What is the total work done on you and your bicycle when you go from the base to the top of the bridge?

Part B
How much work have you done with the force you apply to the pedals?
Physics
1 answer:
Sonja [21]3 years ago
4 0

We have that K.E and work done is

  • K.E=-1890J
  • W=2186J

From the Question we are told that

mass= 80.0 kg

Velocity= 7.50 m/s.

vertical distance of 5.20 m

Slowed to 3.00 m/s.

Generally the equation for Kinetic energy   is mathematically given as

K.E=\frac{mv^2}{2}-\frac{mv^2}{2}\\\\K.E=\frac{80*3^2}{2}-\frac{80*7.5^2}{2}

K.E=-1890J

B)

P.E=mgh\\\\P.E=80*9.8*5.2\\\\P.E=4076

Therefore

W=4076-1890J

W=2186J

For more information on this visit

brainly.com/question/12669551?referrer=searchResults

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Basile [38]
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7 0
3 years ago
An atom contains 15 neutrons and has a mass number of 30. What is its atomic number? How did you determine the atomic number?
irinina [24]

Answer:

15

Explanation:

The mass number is defined as the total number of protons and neutrons. The atomic number is total number of protons. And since we have the mass number and number of neutrons, we can use simple subtraction (30 - 15) to find that the atomic number is 15.

8 0
4 years ago
It is found experimentally that the electric field in a certain region of Earth's atmosphere is directed vertically down. At an
Lemur [1.5K]

Answer:

q=1.7346×10⁻⁶C

Explanation:

Since the electric field is perpendicular to the bottom and top of the cube,the total flux is equals the flux over the top of surface plus the flex over the lower surface

Ф(total)=Ф₃₀₀+Ф₂₃₀

But the flux is given by  Ф=E.A=EACos(θ) where θ is the angle between Area vector and electric field

So

Ф(total)=E₃₀₀A Cos(180)+E₂₃₀ACos(0)

Ф(total)=A(E₃₀₀ - E₂₃₀)

The total flux is given by Gauss Law as:

Ф(total)=q/ε₀

q=ε₀Ф(total)

q=ε₀(A(E₃₀₀ - E₂₃₀))

Substitute the given values

q=(8.85×10⁻¹²){(70²)(100 - 60)}

q=1.7346×10⁻⁶C

7 0
3 years ago
he capacitor can withstand a peak voltage of 550 VV . If the voltage source operates at the resonance frequency, what maximum vo
anygoal [31]

Answer:

The maximum voltage is 39.08 V.

Explanation:

Given that,

Voltage = 550 V

Suppose, In an L-R-C series circuit, the resistance is 400 ohms, the inductance is 0.380 Henry, and the capacitance is 1.20\times10^{-2}\mu F

We need to calculate the resonant frequency

Using formula of resonant frequency

f=\dfrac{1}{2\pi\sqrt{LC}}

Put the value into the formula

f=\dfrac{1}{2\pi\sqrt{0.380\times1.20\times10^{-8}}}

f=2356.8\ Hz

We need to calculate the maximum current

Using formula of current

I=\dfrac{V_{c}}{X_{c}}

I=2\pi f C\times V_{c}

Put the value into the formula

I=2\pi\times2356.8\times1.20\times10^{-8}\times550

I=0.0977\ A

We need to calculate the impedance of the circuit

Using formula of impedance

Z=\sqrt{R^2+(X_{L}-X_{C})^2}

At resonant frequency , X_{L}=X_{C}

So, Z = R

We need to calculate the maximum voltage

Using formula of voltage

V=IR

Put the value into the formula

V=0.0977\times400

V=39.08\ V

Hence, The maximum voltage is 39.08 V.

4 0
3 years ago
A biker pedals with a constant acceleration to reach a velocity of 7.5m/s over 4.5s. During the period of acceleration, the bike
Flura [38]

Given:

v(final velocity)= 7.5 m/s

t(time taken to pedal along)=4.5 s

Displacement (s)=19 m

Now we know that

s=ut+1/2(at^2)

Where s is the displacement measured in m

u is the initial velocity measured in m/sec

a is the acceleration measured in m/s^2.

t is the time taken to cover this distance.

Substituting the given values in the above formula we get

19= 4.5u+1/2(a x 4.5 x 4.5)

20.25 a + 9 u = 38


Now we also know that

v= u + at

Substituting the given values in the above formula we get

7.5= u + 4.5a


Solving for u and a from the above equations we get

u = 0.944m/s

a= 1.45 m/s^2

Thus the initial velocity is 0.944 m/s


7 0
3 years ago
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