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VashaNatasha [74]
3 years ago
15

You and your bicycle have combined mass 80.0 kg. When you reach the base of a bridge, you are travelling along the road at 7.50

m/s. At the top of the bridge, you have climbed a vertical distance of 5.20 m and have slowed to 3.00 m/s. Ignore work done by friction and any inefficiency in the bike or your legs.
Part A
What is the total work done on you and your bicycle when you go from the base to the top of the bridge?

Part B
How much work have you done with the force you apply to the pedals?
Physics
1 answer:
Sonja [21]3 years ago
4 0

We have that K.E and work done is

  • K.E=-1890J
  • W=2186J

From the Question we are told that

mass= 80.0 kg

Velocity= 7.50 m/s.

vertical distance of 5.20 m

Slowed to 3.00 m/s.

Generally the equation for Kinetic energy   is mathematically given as

K.E=\frac{mv^2}{2}-\frac{mv^2}{2}\\\\K.E=\frac{80*3^2}{2}-\frac{80*7.5^2}{2}

K.E=-1890J

B)

P.E=mgh\\\\P.E=80*9.8*5.2\\\\P.E=4076

Therefore

W=4076-1890J

W=2186J

For more information on this visit

brainly.com/question/12669551?referrer=searchResults

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Answers:

a) -171.402 m/s  

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Explanation:

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Where:

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V_{oy}=0 m/s is the bomb's initial vertical velocity, since the airplane was moving horizontally

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Knowing this, let's begin with the answers:

<h3>b) Time </h3>

With the conditions given above, equation (1) is now written as:

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Isolating t:

t=\sqrt{\frac{2 y_{o}}{g}} (5)

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t=17.49 s (7)

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Since V_{oy}=0 m/s, equation (3) is written as:

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Substituting (7) in (2):

x=(97.22 m/s)(17.49 s) (11)

x=1700.99 m (12)

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