What force is needed to give a mass of 20kg an acceleration of 5.0m/s?

What type of heat does not require matter?

Lana71 [14]

It would be Thermal Radiation

4 0

2 years ago

Vector A points along the + y axis and a magnitude of 100.0 units. Vector B points at an angle of 60.0 degrees above the +x axis

DedPeter [7]

Answer:

vector quantities are resolved into their component form (along the x and y-axis) before adding them. Let us assume that two vectors are

→

a

=

x

1

^

i

+

y

1

^

j

and

→

b

=

x

2

^

i

+

y

2

^

j

, we can find the sum of two vectors as follows.

→

a

+

→

b

=

x

1

^

i

+

y

1

^

j

+

x

2

^

i

+

y

2

^

j

=

(

x

1

+

x

2

)

^

i

+

(

y

1

+

y

2

)

^

j

The direction of the sum of the vectors (with positive x-axis) is,

θ

=

tan

−

1

(

y

1

+

y

2

x

1

+

x

2

)

3 0

2 years ago

What is the speed of a bobsled whose distance-time graph indicates that it traveled 100 m in 25 s?

larisa86 [58]

As per the question, the distance travelled by bobsled [s] = 100 m

The time taken by the bobsled to travel that distance [t] = 25 s

We are asked to calculate the speed of the bobsled.

The speed of the bobsled is calculated as -

$speed\ =\ \frac{distance}{time}$

$v\ =\ \frac{s}{t}$

$=\frac{100\ m}{25\ s}$

$=\ 4\ m/s$

Hence, the correct answer to the question is A. 4 m/s.

8 0

3 years ago

A laser source has a bandwidth of 30GHz (a) Calculate the coherence length of the source b) What is the time separation of secti

abruzzese [7]

Explanation:

It is given that,

Bandwidth of a laser source, $f=30\ GHz=30\times 10^9\ Hz$

(b) Let t is the time separation of sections of sections of the light wave that can still interfere. The time period is given by :

$T=\dfrac{1}{f}$

$T=\dfrac{1}{30\times 10^9}$

$T=3.33\times 10^{-11}\ s$

(a) Let h is the coherence length of the source. It is given by :

$l=c\times T$

c is the speed of light

$l=3\times 10^8\times 3.33\times 10^{-11}$

l = 0.0099 m

Hence, this is the required solution.

6 0

2 years ago

If you could travel with speed of light (3.0e5 km/s) it would take only 2.5 minutes to reach venus. how far is venus from earth

motikmotik

D=S/T ,S=3.0e5km/s × 2.5min×60
D=4.5×e6km

7 0

3 years ago