For question number 1:The plot H = H(t) is the parabola and it reaches its maximum in the moment when exactly at midpoint between the roots t = 0 and t = 23. At that moment t = 23/2 or 11.5 seconds.
For question number 2:To find the maximal height, just simply substitute t = 11.5 into the quadratic equation. The answer would be 22.9.
For question number 3:H(t) = 0, or, which is the same as -16t^2 + 368t = 0.Factor the left side to get -16*t*(t - 23) = 0.t = 0, relates to the very start of the process, when the ash started its way up.The other root is t = 23 seconds, and it is precisely the time moment when the bit of ash will go back to the ground.
The space margin depends on light and weather conditions as well as terrain (road curvature, hills, trees or other obstacles).
The time margin depends on the space margin, your reaction time, and your speed of travel.
You may appear to have a lot of time or space in icy conditions, but that can be an illusion. A collision course on ice will result in a collision, regardless of the time or distance involved.
Insufficient information is provided to be more specific.
Answer:
A) 9 photos in each row
B) 14 rows in total
Step-by-step explanation:
Photos of People = 45
Photos of Landscapes = 18
Photos of Pets = 63
Jenny wants to arrange these photos in rows with only one kind of photos in each row and same number of photos in each row. We have to find the greatest possible number of photos in each row. For this we need to find the greatest common factor of 45,18 and 63. This would give us the greatest possible number of photos that can be placed in each row.
By observing the 3 numbers, we can tell that the greatest common factor of these 3 numbers is 9. So, Jenny can place 9 photos in each row.
So,
There will be:
45/9 = 5 rows with photos of people
18/9 = 2 rows of photos of landscapes
63/9 = 7 rows of photos of pets
So, total number of rows would be = 5 + 2 + 7 = 14 rows
