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MArishka [77]
3 years ago
12

A plane is flying at 31,348 feet. It needs to rise to 36,000 feet in two stages. In stage 1, it rises 5% of its initial altitude

of 31,348 feet. In stage 2, it rises at a rate of 140.3 feet per minute. How many minutes does it take for the plane to rise during stage 2?
Mathematics
1 answer:
In-s [12.5K]3 years ago
6 0

Answer:

well, 5% of 31348 is 1567.4

That leaves her 3084.6 feet to go.

And as you know, time = distance/speed

Step-by-step explanation:

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After solving for both variables, you find that each bus can hold 59 students and each van can hold 18 students.

Step-by-step explanation:

You can find the amount of students each vehicle can carry by representing the two scenarios in equations.

You are trying to find how many students will fit in each bus or van, so the two variables used will be "b" to represent how many students can fit in a bus and "v" to represent how many students can fit in a van.

High school A used 1 van and 6 buses, so there will be 1"v" and 6"b" for 372 students.

High school B used 4 vans and 12 buses, so there will be 4"v" and 12"b" for 780 students.

Now, represent these in equations:

v+6b = 372\\4v + 12b = 780

We can use substitution to solve this system:

v + 6b = 372 can be rewritten as v = 372 - 6b after subtracting 6b from both sides. You can then substitute this new value of "v" into the other equation to solve for "b":

4(372-6b) + 12b = 780\\1488 - 24b + 12b = 780\\1488 - 12b = 780\\-12b = -708\\b = 59

After solving for b, you can then substitute the new value of b into the other equation to find the value of v:

v + 6(59) = 372\\v + 354 = 372\\v = 18

After solving for both variables, you find that each bus can hold 59 students and each van can hold 18 students.

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Step-by-step explanation:

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