Answer:
ok
Step-by-step explanation:
Answer: =10x+8y−12
Step-by-step explanation:
Let's simplify step-by-step.
−6x−12+8y+16x
=−6x+−12+8y+16x
Combine Like Terms:
=−6x+−12+8y+16x
=(−6x+16x)+(8y)+(−12)
=10x+8y+−12
Answer:
=10x+8y−12
Answer:
all real numbers
Step-by-step explanation:
Here is the solution to the first inequality:
3(2x +1) > 21 . . . . . . given
6x +3 > 21 . . . . . . . . eliminate parentheses
6x > 18 . . . . . . . . . . .subtract 3
x > 3 . . . . . . . . . . . . divide by 6
This is all numbers to the right of 3 on the number line.
__
The solution to the second inequality is ...
4x +3 < 3x + 7 . . . . given
x < 4 . . . . . . . . . . . . subtract 3x+3
This is all numbers to the left of 4 on the number line.
__
The conjunction in the system of inequalities is "or", so we are looking for values of x that will satisfy at least one of the conditions. <em>Any value of x</em> will satisfy one or the other or both of these inequalities. The solution is all real numbers.
Remember to use trig form the general equation is: r(cos(angle) + i sin(angle))
to find r, take √a^2 + b^2 to get 3 for the angle it would be undefined so thee argument would be π / 2. So your answer is 3(cos(π/2) + i sin(π/2))
The equation of the function f with solution 3, -9 is x²+6x-27 and the graph of this equation with the use of drawing tools is attached below.
<h3>What is the definition of a Function?</h3>
A function assigns the value of each element of one set to the other specific element of another set.
A function has to be plot which has the value of f(x) as 3 and -9. Here, 3 and -9 are the solution of the function. Thus,
x=3
x-3=0
The second solution is,
x=-9
x+9=0
Multiply both factor for the function as,
f(x)=(x-3)(x+9)
f(x)=x²+9x-3x-27
f(x)=x²+6x-27
This is the required function. The graph of this function is attached below.
Thus, the equation of the function f with solution 3, -9 is x²+6x-27 and the graph of this equation with the use of drawing tools is attached below.
Learn more about Function here:
brainly.com/question/5245372
#SPJ1