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shusha [124]
3 years ago
10

What is the importance of natural resources ?write 5 points ​

Physics
1 answer:
Whitepunk [10]3 years ago
5 0
<h2>Hey there! </h2>

<h2>Natural Resource:</h2>

  • The resources, for example, sunshine, air, water, soil, plants, animals, minerals, rivers etc. which after natural formation remain distributed on the earth, are known as natural resource.
  • The natural resources are found in solid, liquid or gaseous states, and in metallic or non metallic form.

<h2>Hope it help you </h2>
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A binary star system consists of two equal mass stars that revolve in circular orbits about their center of mass. The period of
Vladimir79 [104]

Answer:

m = 2.23 \times 10^{-32} kg

Explanation:

Given data:

PERIOD OF MOTION IS T = 25.5 days

orbital speeds = 220 km/s

we know that

acceleration due to centripetal force isa =   \frac{F}{m} = \frac{V^2}{r}

Gravitational forceF= \frac{Gm m}{d^2}

we know that

v = \frac{2\pi R}{T}

solving for

R = \frac{vT}{2\pi}

F = \frac{Gm^2}{4(\frac{vT}{2\pi})^2}

F = G\times \frac{\pi m}{(vT)^2}

a = \frac{v^2}{\frac{vT}{2\pi}}

a = \frac{2\pi v}{T}

we know that

f =ma

G\times \frac{\pi m}{(vT)^2} = a = \frac{2\pi m v}{T}

solving for m

m = \frac{2Tv^3}{\pi G}

m = \frac{2\times 25.5 \times 86400 \times 220000^3\ m/s}{\pi \times 6.67\times 10^{-11}}

m = 2.23 \times 10^{-32} kg

5 0
3 years ago
1. Place these unknown pH test papers in order from most acidic to most alkaline.
Naddika [18.5K]

Answer: B

Explanation: look at the chart, easy

7 0
3 years ago
HELP PLZ ASAP!!!!!
zubka84 [21]

Answer:

C. Oxygen combines with carbon dioxide

Explanation:

B i o l o g y

Also, oxygen is a reactant and carbon dioxide is a product of cellular respiration that does not combine during this process

Hope it helps

5 0
3 years ago
The electric field between two parallel plates is uniform, with magnitude 628 N/C. A proton is held stationary at the positive p
aliina [53]

Answer:

Answer is explained in the explanation section below.

Explanation:

Solution:

Data Given:

Electric Field between two parallel plates = 628 N/C

Separation = 4.22 cm

a) In this part, we are asked to calculate the distance from positive plate at which the electron and proton pass each other.

Solution:

First of all:

Force on proton due to the Electric field between the plates is:

F_{p} = q_{p}E

and, we know that, F = ma

So,

m_{p}a = q_{p}E

a = \frac{q_{p}.E }{m_{p} }      Equation 1

So,

The distance covered by the electron is:

S = ut + 1/2at^{2}

Here, u = 0.

S = 1/2at^{2}

Put equation 1 into the above equation:

S = 1/2 x (\frac{q_{p}.E }{m_{p} }  )t^{2}      Equation 2

So,  

Similarly, the distance covered by electron will be:

(D-S) = 1/2 x (\frac{q_{e}.E }{m_{e} }  )t^{2}    Equation 3

We know that the charge of electron is equal to the charge of proton so,

q_{p} = q_{e} = q

By dividing the equation 2 by equation 3, we get:

\frac{S}{D-S} = \frac{m_{e} }{m_{p} }

Solve the above equation for S,

Sm_{p} = m_{e}D - m_{e}S

So,

S = \frac{m_{e}.D }{(m_{e} + m_{p})  }

Plugging in the values,

As we know the mass of electron is 9.1 x 10^{-31} and the mass of proton is 1.67 x 10^{-27}

S = \frac{9.1 . 10^{-31} . 4.22 }{(9.1 . 10^{-31} + 1.67 . 10^{-27}  }

S = 0.002298 cm (Distance from the positive plate at which the two pass each other)

b) In this part, we to calculate distance for Sodium ion and chloride ion as above.

So,

we already have the equation, we need to put the values in it.

So,

S = \frac{m_{Cl}.D }{(m_{Cl} + m_{Na})  }

As we know the mass of chlorine is 35.5 and of sodium is 23

S = \frac{35.5 . 4.22}{(35.5 + 23)}

S = 2.56 cm

7 0
3 years ago
Which are characteristics of concave mirrors? Check all that apply.
aalyn [17]

Answer:

the answers are 1 2 and 5!

5 0
4 years ago
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