Answer:
11.9 years
Explanation:
We can find the orbital period by using Kepler's third law, which states that the ratio between the square of the orbital period and the cube of the average distance of a planet from the Sun is constant for every planet orbiting aroudn the Sun:
Using the Earth as reference, we can re-write the law as
where
Te = 1 year is the orbital period of the Earth
re = 1 AU is the average distance of the Earth from the Sun
Tj = ? is the orbital period of Jupiter
rj = 5.20 AU is the average distance of Jupiter from the Sun
Substituting the numbers and re-arranging the equation, we find:
Answer:
c. 43 m/s
Explanation:
Given the following data;
Displacement, S = 90 meters
Time, t = 5.55 seconds
To find the initial velocity;
We would use the second equation of motion given by the formula;
Where;
- S represents the displacement or height measured in meters.
- u represents the initial velocity measured in meters per seconds.
- t represents the time measured in seconds.
- a represents acceleration measured in meters per seconds square.
We know that acceleration due to gravity is -9.8m/s² because the direction is downward.
Substituting into the equation, we have;
Rearranging the equation, we have;
Initial velocity, u = 43.41 ≈ 41 m/s
B......................... <span>Yes they do!</span>
There are 8 hydrogen atoms
