Answer:
The stress S = 1935 [Psi]
Explanation:
This kind of problem belongs to the mechanical of materials field in the branch of the mechanical engineering.
The initial data:
P = internal pressure [Psi] = 90 [Psi]
Di= internal diameter [in] = 22 [in]
t = wall thickness [in] = 0.25 [in]
S = stress = [Psi]
Therefore
ri = internal radius = (Di)/2 - t = (22/2) - 0.25 = 10.75 [in]
And using the expression to find the stress:
In the attached image we can see the stress σ1 & σ2 = S acting over the point A.
