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Dmitrij [34]
3 years ago
12

Metric conversions. Please help ASAP.

Chemistry
1 answer:
lesya692 [45]3 years ago
7 0

Answer:

14. 13.2cg = 1.32dg

15. 3.8m = 0.0038km

16. 24.8L = 24800mL

17. 0.87kL = 870L

18. 26.01cm = 0.0002601km

19. 0.001hm = 10cm

Explanation:

14. 13.2/10 = 1.32

15. 38/1000 = 0.0038

16. 24.8(1000) = 24,800

17. 0.87(1000) = 870

18. 26.01/100000 = 0.0002601

19. 0.001hm(10000) = 10

An easy way to do these by yourself is to familiarize yourself with what each prefix means. Once you do this, you can multiply the value of the prefix when converting from a smaller unit of measurement to a larger one and divide the value of the prefix when converting from a large unit of measurement to a smaller one.

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What types of questions can be answered through science and what questions are beyond the boundaries of science? Be specific and
Anna [14]
The questions tha science can answer are those can be tested to try to find a definite answer.

For example, whether light is wave or particle is matter of science.

Questions that cannot have a definite answer are the field of religion or philosophy, and are out of the boundaries of science.

For example, does a criminal deserve the punishment of not seeing light? It is a moral question, which to be responded needs the intervention of philosophy and that could have different anwers at different times and in different societies.

 


3 0
3 years ago
A student investigates the properties of an unknown liquid substance in a beaker. The student finds the substance has a mass of
shtirl [24]

Answer:

The substance is a mixture because it left a white powder in the beaker when boiled.

Explanation:

8 0
3 years ago
The powder mixture (Cu, Al and Fe) = 10g was oxidized from sufficient chloride acid. 1) What are the possible reactions to the p
Mandarinka [93]

Answer:

1) 2Al + 6HCl ⟶ 2AlCl₃ + 3H₂

    Fe + 2HCl ⟶ FeCl₂ + H₂

2) Cu = 2.5 g; Al = 3.5 g; Fe = 4.0 g  

Explanation:

1) Possible reactions

2Al + 6HCl ⟶ 2AlCl₃ + 3H₂

Fe + 2HCl ⟶ FeCl₂ + H₂

2) Mass of each metal

a) Mass of Cu

The waste was the unreacted copper.

Mass of Cu = 2.5 g

b) Masses of Al and Fe

We have two relations :

Mass of Al + mass of Fe = 10 g - 2.5 g = 7.5 g

H₂ from Al + H₂ from Fe = 6.38 L at NTP

i) Calculate the moles of H₂

NTP is 20 °C and 1 atm.

\begin{array}{rcl}pV & = & n RT\\\text{1 atm} \times \text{6.38 L} & = & n \times 0.08206 \text{ L}\cdot\text{atm}\cdot\text{K}^{-1}\text{mol}^{-1} \times \text{293.15 K}\\6.38 & = & 24.06n \text{ mol}^{-1} \\n & = & \dfrac{6.38}{24.06 \text{ mol}^{-1} }\\\\ & = & \text{0.2652 mol}\\\end{array}

(ii) Solve the relationship

 Let x = mass of Al. Then

7.5 - x = mass of Fe

Moles of Al = x/27

Moles of Fe = (7.5 - x)/56

Moles of H₂ from Al = (3/2) × Moles of Al = (3/2) × (x/27) = x /18

Moles of H₂ from Fe = (1/1) × Moles of Fe = (7.5 - x)/56

∴ x/18 + (7.5 - x)/56 = 0.2652

    56x + 18(7.5 - x) = 267.3

      56x + 135 - 18x = 267.3

                        38x = 132.3

                            x = 3.5 g

Mass of Al = 3.5 g

Mass of Fe = 7.5 g - 3.5 g = 4.0 g

The masses of the metals are Cu = 2.5 g; Al = 3.5 g; Fe = 4.0 g

4 0
4 years ago
What would happen to the sup- ply of ATP in your cells if you did not eat enough carbohydrates? How would this affect your cells
harina [27]

Answer:

ATP supply will reduced or decrease drastically

Explanation:

ATP will reduced because carbohydrates are energy given food. Chemical energy are in carbohydrates, therefore when the undergo digestion i.e breakdown of larger pieces into smaller pieces, it is broken down into glucose i.e energy is released. Therefore, if there is now carbohydrates, ATP supply will reduced and there won't be energy needed for different cellular metabolic activities. The breakdown of carbohydrate supply energy.

3 0
3 years ago
A gas occupies 3.5L at 2.5 kPa pressure. What is the volume at 100 mmHg at the same temperature? Be sure to
nasty-shy [4]

The volume at 100 mmHg : 0.656 L

<h3>Further explanation</h3>

Boyle's Law  

<em>At a constant temperature, the gas volume is inversely proportional to the pressure applied  </em>

\rm p_1V_1=p_2.V_2\\\\\dfrac{p_1}{p_2}=\dfrac{V_2}{V_1}

V₁=3.5 L

P₁=2.5 kPa=18,7515 mmHg

P₂=100 mmHg

\tt \dfrac{18.7515}{100}=\dfrac{V_2}{3.5}\\\\V_2=\dfrac{18.7515\times 3.5}{100}=0.656~L

4 0
3 years ago
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