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Dmitrij [34]
3 years ago
12

Metric conversions. Please help ASAP.

Chemistry
1 answer:
lesya692 [45]3 years ago
7 0

Answer:

14. 13.2cg = 1.32dg

15. 3.8m = 0.0038km

16. 24.8L = 24800mL

17. 0.87kL = 870L

18. 26.01cm = 0.0002601km

19. 0.001hm = 10cm

Explanation:

14. 13.2/10 = 1.32

15. 38/1000 = 0.0038

16. 24.8(1000) = 24,800

17. 0.87(1000) = 870

18. 26.01/100000 = 0.0002601

19. 0.001hm(10000) = 10

An easy way to do these by yourself is to familiarize yourself with what each prefix means. Once you do this, you can multiply the value of the prefix when converting from a smaller unit of measurement to a larger one and divide the value of the prefix when converting from a large unit of measurement to a smaller one.

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What is the acceleration of a 5 kg mass pushed by a 10 N force?
Olin [163]

Answer:

Here the force is 10N and the mass is 5 kg. Dividing both sides by 5kg, we get a = 2 m/s^2.

5 0
3 years ago
A solid piece of lead has a mass of 23.94g and a volume of 2.10cm^3. from these data, calculate the density of lead in si units
jeyben [28]
A density of a substance is constant. It is an extensive property, meaning it does not depend on the amount of substance because it is a ratio of mass to volume. No matter how much of each there is, they would always have a fixed ratio called density. For lead, the density is

Density = mass/volume
Density = 23.94 g/ 2.10 cm³
Density = 11.4 g/cm³
4 0
3 years ago
Identify one disadvantage to each of the following models of electron configuration
8_murik_8 [283]

Answer:

The disadvantages or the limitations are as follows:

Dot structures: based on an empirical trend “atoms like octets”, not a rigorous description of the true nature of electrons

Arrow and line diagrams: Does not say much of the possible properties of the molecule.

Written electron configurations: no 3D representation of the molecule or the atom

Explanation:

please mark my answer as brain list

3 0
4 years ago
A student prepares a aqueous solution of trimethylacetic acid . Calculate the fraction of trimethylacetic acid that is in the di
irinina [24]

The question is incomplete, here is the complete question:

A student prepares a 0.21 mM aqueous solution of trimethylacetic acid. Calculate the fraction of trimethylacetic acid that is in the dissociated form in his solution. Express your answer as a percentage. You will probably find some useful data in the ALEKS Data resource. Round your answer to 3 significant digits.

<u>Answer:</u> The percent of dissociation of trimethylacetic acid is 19.5 %

<u>Explanation:</u>

We are given:

Concentration of trimethylacetic acid = 0.21 mM  = 0.00021 M    (Conversion factor:  1 mole = 1000 millimoles )

The chemical equation for the dissociation of trimethylacetic acid follows:

                     C_4H_9COOH\rightleftharpoons C_4H_9COO^-+H^+

<u>Initial:</u>                   0.00021

<u>At eqllm:</u>             0.00021-x              x            x

The expression of K_a for above equation follows:

K_a=\frac{[C_4H_9COO^-][H^+]}{[C_4H_9COOH]}

We know that:

K_a\text{ for }C_4H_9COOH=1\times 10^{-5}

Putting values in above expression, we get:

1\times 10^{-5}=\frac{x\times x}{(0.00021-x))}\\\\x=0.000041,-0.000051

Neglecting the negative value of 'x' because concentration cannot be negative.

To calculate the fraction of dissociation, we use the equation:

\text{Percent of dissociation}=\frac{[H^+]}{[C_4H_9COOH]}\times 100

Putting values in above equation, we get:

\text{Percent of dissociation}=\frac{0.000041}{0.00021}\times 100\\\\\text{Percent of dissociation of trimethylacetic acid}=19.5%

Hence, the percent of dissociation of trimethylacetic acid is 19.5 %

8 0
3 years ago
Can some someone plz help
Semmy [17]

Answer:

ummmmmmmmmmmmmmmmmmmm

5 0
3 years ago
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