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Fudgin [204]
2 years ago
10

How many grams of barium sulfate form when 35.0 ml of 0.160 m barium chloride reacts with 58.0 ml of 0.065 m sodium sulfate? do

not list units in your answer. stick to three sig figs.
Chemistry
1 answer:
vazorg [7]2 years ago
3 0

Barium sulfate weighs 0.88 grams per gram.

Mass:

A physical body's overall composition is measured by its mass.

Inertia, or the body's resistance to acceleration in the presence of a net force, is also measured by it.

The mass of a thing also affects how strongly it attracts other bodies through gravity.

In the SI, the kilogram serves as the basic mass unit (kg).

This information

Moles of BaCl2 equal 5.6 x 103 (35 x 0.160 / 1000)

sodium sulfate moles equal 58 x 0.065, or 3.77 x 103,

Na2SO4 with BaCl2 ——————————-> 2NaCl plus BaSO4

Na2SO4 is the limiting agent here.

Therefore, the product relies on limiting reagent.

1 mol of Na2SO4 produces 1 mol of BaSO4.

0.00377 moles of BaSO4 is one mole.

moles = mass / molar mass of BaSO4.

0.00377 = mass / 233.4

BaSO4 mass is 0.88 g.

So, 0.88 grams of barium sulfate make up one gram.

To know more about the mass visit:

brainly.com/question/28204586

#SPJ4

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Which of the following compounds are soluble in aqueous solutions? Select ALL that are soluble.
sattari [20]
<h3>Answer:</h3>
  • K₂S
  • CaSO₄ (slightly soluble in water)
  • Pb(ClO₄)₂
<h3>Explanation:</h3>
  • Mg(OH)₂  and CoCO₃ are insoluble in water.
  • Solubility rules are used to determine whether a compound will be soluble or not soluble in aqueous form.
  • K₂S is soluble in aqueous solutions as all salts of Potassium are soluble in water.
  • Calcium (ii) sulfate is slightly soluble in water.
  • Hydroxides are insoluble in water except, KOH, NaOH and NH₄OH.and Barium hydroxide. Therefore, Mg(OH)₂ is an insoluble hydroxide.
  • CoCO₃ is insoluble since carbonates are insoluble except K₂CO₃, Na₂CO₃ and (NH₄)₂CO₃. .
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7 0
3 years ago
A community consists of all the organisms in an ecosystem that belong to the same species.
choli [55]

Answer:

False

Explanation:

A community consists of all the organisms in an ecosystem that belong to the same species. Population density occurs when two or more organisms seek the same resource at the same time. A carrying capacity is anything that restricts the number of individuals in a population.

3 0
2 years ago
Read 2 more answers
A sample of Manganese (II) chloride has a mass of 19.8 grams before heating, and 12.6 grams after heating until all the water is
IRINA_888 [86]

Answer:

no. of water molecules associated to each molecule of MnCl_2 = 4

Explanation:

Mass of MnCl_2 before heating = 19.8 g

Mass of MnCl_2 after heating = 12.6 g

Difference in mass of MnCl_2 before and after heating

                                 = 19.8 - 12.6 = 7.2 g

Difference in mass corresponds to mass of water driven out.

Molar mass of water = 18 g/mol

No. of moles of water = \frac{7.2}{18} = 0.4\ mol

Mass of MnCl_2 obtained after heating is mass of anhydrous MnCl_2.

Mass of anhydrous MnCl_2 = 12.6 g

Molar mass of MnCl_2 = 125.9 g/mol

No. of mol of anhydrous MnCl_2 = \frac{125.9}{125.9} = 0.1\ mol

so,

0.1 mol of MnCl_2 have 0.4 mol of water

1 mol of MnCl_2 will have = \frac{0.4}{0.1} =4\ mol

Hence, no. of water molecules associated to each molecule of MnCl_2 = 4

5 0
3 years ago
A fuel scientist burnt a piece of coal and a piece of wood to compare the amount of heat given off by each. Which is the correct
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4 0
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3) A child has a toy balloon with a volume of 1.8 liters. The temperature of the balloon when it was filled was 22° C and the pr
mestny [16]

This is a combined gas law problem, according to which

\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}

where P is the pressure of the gas, V is the volume of the gas, and T is the temperature of the gas, and the subscripts 1 and 2 correspond to the initial and final conditions of the gas. In this problem, we are given the initial pressure, volume, and temperature of the gas in the balloon:

P₁ = 1.0 atm

V₁ = 1.8 L

T₁ = 295.15 K (K = °C + 273.15).

Moreover, we are given the final pressure and temperature of the gas in the balloon.

P₂ = 0.86 atm

T₂ = 281.15 K.

What we want to find is the final volume, V₂, which we can obtain by rearranging the combined gas equation to solve for V₂:

V_2=\frac{P_1V_1T_2}{T_1P_2} = \frac{(1.0 \text{ atm})(1.8 \text{ L})(281.15 \text{ K})}{(295.15 \text{ K})(0.86 \text{ atm})} \\ V_2 = 1.99 \text{ L}

This answer has three significant figures. However, the question as written would warrant an answer that comprises one significant figure (as 8 °C has only one sig fig). In that case, the answer would be 2 L. If the answer is to be given to two significant figures, the volume would then be 2.0 L.

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