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Assuming that the ammonium sulfide formula is (NH4)2S then you can see that there are 2 nitrogen, 8 hydrogen and 2 sulfur atoms for every ammonium sulfide.
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<span>There are three isotopes of hydrogen H-1, H-2, and H-3 all of these isotopes have "One Proton"
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Answer:
0.0585 M
Explanation:
- Pb(NO₃)₂ (aq) + 2NaCl (aq) → PbCl₂ (s) + 2NaNO₃ (aq)
First we <u>calculate the inital number of moles of each reagent</u>, using the <em>given volumes and concentrations</em>:
- 0.255 M Pb(NO₃)₂ * 52.1 mL = 13.3 mmol Pb(NO₃)₂
- 0.415 M NaCl * 38.5 mL = 16.0 mmol NaCl
Then we <u>calculate how many Pb(NO₃)₂ moles reacted with 16.0 mmoles of NaCl</u>, using the <em>stoichiometric coefficients of the reaction</em>:
- 16.0 mmol NaCl *
= 8.00 mmol Pb(NO₃)₂
Now we <u>calculate the remaining number of Pb(NO₃)₂ moles after the reaction</u>:
- 13.3 mmol - 8.00 mmol = 5.30 mmol Pb(NO₃)₂
Finally we <em>divide the number of moles by the final volume</em> to <u>calculate the concentration</u>:
- 5.30 mmol / (52.1 mL + 38.5 mL) = 0.0585 M
Answer:
atoms are neutral or they have equal number of proton and electron but ions can be cation(positively charged) or anion(negatively charged) based on the number of electron the atm lose and gain respectively