They are uniform in the amount of protons and electrons but can differ in the amount of neutrons.
The correct answer is 0.16138
<u>Solution:</u>
Percentage transmission (%T) of the sample = 15.6
Therefore, Absorbance (A) 2 – log (%T) = 2 – log (15.6) = 0.8069
<u>Use Beer’s law:</u>
A = ε*c*l where ε = molar absorptivity of the solution, c = concentration of the solution, and l = path length of the solution.
Given A = 0.8069 and l = 5.00 cm, we must have
<u>0.8069 = ε*c*(5.00 cm)</u>
ε*c = 0.16138 cm-1
For the next part, assume that ε*c remains constant and we have
A’ = ε*c*l’ where l = 1.00 cm.
Plug in values and write
A’ = (0.16138 cm-1)*(1.00 cm) = 0.16138
The ratio of the light intensity entering the sample to the light intensity exiting the sample at a particular wavelength is defined as the transmittance. Absorption and transmission are two related and different quantities used in spectroscopy. The main difference between absorption and transmission is that absorption measures how much incident light is absorbed as it travels through the material, while transmission measures how much light is transmitted.
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Answer:
I think it would be a solution..
But I'm not sure.
I think that because you said before before blending.
Answer:
d≈ 1.15 g/cm^3
Explanation:
The density of an object can be found by dividing the mass over the volume.
d= m/v
The mass of the object is 54.3 grams and the volume is 47.18 cubic centimeters.
m= 54.3 g
v= 47.18 cm^3
Substitute the values into the formula.
d= 54.3 g/ 47.18 cm
Divide.
d= 1.150911403136922 g/cm^3
Let’s round to the nearest hundredth. The 0 in the thousandth place tells us to leave the 5 in the hundredth place.
d ≈ 1.15 g/cm^3
The density is about 1.15 grams per cubic centimeter.
Answer: 20L of H2O
Explanation:
C3H8 + 5O2 → 3CO2 + 4H2O
Recall 1mole of a gas contains 22.4L at stp
5moles of O2 contains = 5 x 22.4 = 112L
4moles of H2O contains = 4 x 22.4 = 89.6L
From the equation,
112L of O2 produced 89.6L H2O
There for 25L of O2 will produce XL of H2O i.e
XL of H2O = (25 x 89.6)/112 = 20L
