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azamat
2 years ago
13

In what industry is labour likely to be the most important factor of production

Business
1 answer:
Lisa [10]2 years ago
4 0

Answer:

Labour is an active factor of production. It is the factor that starts production. Land and Capital alone cannot start production, so they are passive factors. They need the active factor of production, i.e. labour to be productive themselves.

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Which of the following is not a disadvantage to inflation targeting?
Irina18 [472]

Answer:

D is the correct option

Explanation:

Enhancement of transparency and reduction of price variability are the two advantages of the inflation targeting. Inflation targeting allows the central bank to maintain low inflation. Low inflation promotes long term growth. Enhanced financial growth and reduction in relative price availability are other benefits of inflation targeting. With inflation-targeting central banks can set long term inflation objectives. Increasing accountability and transparency in monetary policy are other benefits. It also helps to predict inflation maintain price stability

5 0
3 years ago
Under which of the following conditions will the FIFO method produce the same cost of goods manufactured as the weighted-average
joja [24]

Answer: The correct answer is <u>".B. There is no beginning inventory.".</u>

Explanation:  

The weighted average method produces the same cost of manufactured goods as the FIFO method (First in First out) when there is no beginning inventory because there are no units at the beginning that drag the cost.

7 0
4 years ago
Leaping Deer Company purchased a tractor at a cost of $240,000. The tractor has an estimated residual value of $40,000 and an es
trapecia [35]

Answer:

Units of production method: $76,820

Explanation:

The three most common depreciation methods are: straight line, double-declining, and units of production. We will calculate the depreciation expense for each.

Straight line method:

Depreciable amount= cost - residual value

                                 = 240,000 - 40,000

                                = 200,000

Depreciation by year = depreciable amount / years of useful life

                                   = 200,000 / 8

                                   = 25,000

Double declining method

Depreciation per year = depreciable amount x (2 / useful life in years)

                      = 200,000 x (2 / 8)

                      = 50,000

Units of production method

Depreciation per unit  = depreciable amount / hours of operation

                                     = 200,000 / 12,000

                                     = 16.7

Total depreciation = depreciation per unit x actual units of operation

                              = 16.7 x 2,400 + 2,200

                              = 16.7 x 4,600

                              = 76.820

Therefore, the units of production method results in the highest depreciation expense among the three.

   

3 0
3 years ago
Wizard Co. purchased two machines for $250,000 each on January 2, 2005.
Vikki [24]

Answer:

B. $275,000

Explanation:

The second machine will be depreciate over time as it can later be used for operational purposes or another research projects. The first, as can only be used for a  research project It should be considered expenses for the entire amount regardless of the useful life.

Machine B useful life 10 years

depreciation expense: cost / useful life

250,000 / 10 = 25,000

machine A 250,000 + 25,000 depreciation for machine B = 275,000 total

7 0
3 years ago
Kelly Malone plans to have $51 withheld from her monthly paycheck and deposited in a savings account that earns 12% annually, co
natita [175]

Answer:

$1,774.2

Explanation:

Compute the accumulated amount in the account on the date of last deposit'

Formula used to find out the future value ordinary annuity is:

Future value factor of ordinary annuity (FVF-0A =_{n,i} ) = \frac{1-(1+i^)^ {n} }{i}

1- oily Future value of ordinary annuity (FV-OA) = R (FVF-0A_{n,i} )

Where:

R = annual return (ordinary annuity)

(FVF-0A_{n,i} ) = future value of an ordinary annuity of I for n periods at i interest

Substituting the values:

Future value of ordinary annuity (FV-OA) = R (FVF-0A_{n,i} )

                                                             = $50 (FVF-OA 12_{2.5X 12\frac{12}{12}  }  )

                                                              =$50 X 34.7849

51 X 34.7849\\=1,774

                                                    

6 0
3 years ago
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