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Sladkaya [172]
3 years ago
13

Y= -3x+6 and y=1/3x-8

Mathematics
2 answers:
yarga [219]3 years ago
8 0

Step-by-step explanation:

Simplify  −3(3 y+24)+6.Y=  −9 y−66 x=     3 y+24

aleksandrvk [35]3 years ago
5 0

Answer:

Y = − 9 y − 66  

x = 3 y + 24

Step-by-step explanation:

Hope this helps!

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A hula hoop measures 14 inches from the center to the outside. What is the distance around the hula
Paladinen [302]

Answer:

43.96

Step-by-step explanation:

5 0
2 years ago
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2/3(x+6)=-18 I need the answer help me!!
iragen [17]

Answer:

x = -33

Step-by-step explanation:

2/3(x+6) = -18

multiply (x+6) by 2/3

2/3x + 4 = -18

subtract 4 from both sides

2/3x + 4 - 4 = -18 - 4

2/3x = -22

multiply by 3/2

2/3 x 3/2 x = -22 x 3/2

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3 years ago
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Find the slope of the line graphed below. PLEASE HELP ME
kap26 [50]

Answer:

-3/5

Step-by-step explanation:

I was always taught rise over run. count how many units up/down the next point is and how many units over.

6 0
3 years ago
Rewrite the expression using the GCF and distributive property. (110-44)
Afina-wow [57]

let me divide your question into two parts A and B as;

A.Rewrite the expression using the GCF and distributive property. (110-44)

B.how many 24-foot jump ropes can be made from a rope that is 100 feet long?

Answer:

A.(110-44)=22(5-2)

B. 4 jump ropes of 24 feet length

Step-by-step explanation:

A.Rewrite the expression using the GCF and distributive property. (110-44

Answer:

Find the GCF of 110 and 44 then take that GCF as common factor out of (110-44) then we can get new expression for (110-44) as 22(5-2) i.e.

prime factorization of 110=2x5x11

and 44=2x2x11

GCf is the product of factors that appear in both of the prime factorization which is 2x11=22

thus using GCF (22) as common factor we can rewrite the given expression as

22(5-2) which is distributive law of multiplication over subtraction.

B.how many 24-foot jump ropes can be made from a rope that is 100 feet long?

Answer:

Given

Total length of the rope =100 feet

length of a jump rope =24

solution:

For one jump-rope we need 24 feet

For two jump-ropes we need 48 feet

For three jump-ropes we need 72 feet

For four jump-ropes we need 96 feet

thus from a 100 feet long rope we can make 4 jump-ropes of 24 feet length with 6 feet remaining as extra.

3 0
3 years ago
1178 × 125 = show work
zlopas [31]
1178x100=117800

1178x20=23560

1178x5=5890

117800+23560+5890=147250
7 0
3 years ago
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