Forces exerted by the jet on the plate is=3976N
<h3>How to calculate forces exerted by the jet on the plate?</h3>
A force is an effect that can change the motion of an object. A force can generate an object with mass to change its velocity, i.e., to accelerate. Force can also be explained intuitively as a push or a pull. A force has both volume and direction, making it a vector amount.
A jet of water 75m in diameter
velocity = 30m/s
The forces exerted by the jet on the plate is
F=1000×44178×10^-3×30²
=3976N
the jet on the plate work done by Is zero .
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Ceramics must be heated in order to harden the clay and make it durable. The tool used to heat the clay is called a Kiln.
<h3>What happens when ceramic is heated?</h3>
Cristobalite is a silica polymorph that is used in ceramics. Quartz particles in porcelain can change into cristobalite during burning. This has effects on the fired matrix's thermal expansion. When there is a high level of vitrification or a shape is unstable during the firing of ceramic ware, warping occurs.
Ceramic items are porous, brittle, and rigid. They are thus employed in the production of glass, ceramics, cement, and bricks. Additionally, ceramics are employed extensively in gas turbine engines. Artificial bones and dental implants are both made of bio-ceramics.
Any of the several tough, fragile, heat- and corrosion-resistant materials created by sculpting and then heating an inorganic, nonmetallic material like clay to a high temperature are known as ceramics.
In order to solidify the clay and make ceramics durable, heat must be applied. A kiln is the name of the device used to heat clay.
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Answer:
- def median(l):
- if(len(l) == 0):
- return 0
- else:
- l.sort()
- if(len(l)%2 == 0):
- index = int(len(l)/2)
- mid = (l[index-1] + l[index]) / 2
- else:
- mid = l[len(l)//2]
- return mid
-
- def mode(l):
- if(len(l)==0):
- return 0
-
- mode = max(set(l), key=l.count)
- return mode
-
- def mean(l):
- if(len(l)==0):
- return 0
- sum = 0
- for x in l:
- sum += x
- mean = sum / len(l)
- return mean
-
- lst = [5, 7, 10, 11, 12, 12, 13, 15, 25, 30, 45, 61]
- print(mean(lst))
- print(median(lst))
- print(mode(lst))
Explanation:
Firstly, we create a median function (Line 1). This function will check if the the length of list is zero and also if it is an even number. If the length is zero (empty list), it return zero (Line 2-3). If it is an even number, it will calculate the median by summing up two middle index values and divide them by two (Line 6-8). Or if the length is an odd, it will simply take the middle index value and return it as output (Line 9-10).
In mode function, after checking the length of list, we use the max function to estimate the maximum count of the item in list (Line 17) and use it as mode.
In mean function, after checking the length of list, we create a sum variable and then use a loop to add the item of list to sum (Line 23-25). After the loop, divide sum by the length of list to get the mean (Line 26).
In the main program, we test the three functions using a sample list and we shall get
20.5
12.5
12
