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3 years ago

An organized plan for a gathering, organization, and communication information is called a(n) _____

Physics

1 answer:

natta225 [31]3 years ago

4 0

Scientific Method also known as a Scientific Approach.

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On a grid, what is the distance between two points located at (1, 1) and (8, 4) roughly equal to?

Diano4ka-milaya [45]

Ithink the answer is a

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3 years ago

A punted football hits the ground with a force of 50 N . According to Newton’s 3rd law of motion what also happens at the same e

Nadya [2.5K]

As per Newton's III law every action has equal and opposite reaction

So here we can say that

every body which apply force on other body must have a reaction force of same magnitude in opposite direction

So here if ball hits the ground by 50 N force then the ball must have a reaction force on itself with same magnitude and opposite direction

the magnitude of the force will be 50 N

and its direction is opposite to the force that ball apply on the floor

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3 years ago

A shopper pushes a 5.32 kg grocery cart with a 12.7 N force directed at -28.7° below horizontal. A friction force of 8.33 N push

atroni [7]

Answer:

0.8214 m/s^2

Explanation:

Fnet= Fpushed - Ffriction

Fpushed = 12.7N Ffriction = 8.33N

Fnet = 12.7N - 8.33N = 4.37N

Fnet= mass(acceleration)

Fnet = 4.37N mass = 5.32 kg

4.37N = 5.32 kg(acceleration)

acceleration= 0.8214 m/s^2

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3 years ago

I will do ALL of your school work!!

kakasveta [241]

Answer:

get it done for free on www.brainly.com

Explanation:

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3 years ago

Read 2 more answers

A tuning fork labeled 392 Hz has the tip of each of its two prongsvibrating with an amplitude of 0.600mma) What is the maximum s

DanielleElmas [232]

a) 1.48 m/s

The tuning fork is moving by simple harmonic motion: so, the maximum speed of the tip of the prong is related to the frequency and the amplitude by

$v_{max}=\omega A$

where

$v_{max}$ is the maximum speed

$\omega$ is the angular frequency

A is the amplitude

For the tuning fork in the problem, we have

$\omega=2\pi f=2 \pi(392 Hz)=2462 rad/s$ , where f is the frequency

$A=0.600 mm=6\cdot 10^{-4} m$ is the amplitude

Therefore, the maximum speed is

$v_{max}=(2462 rad/s)(6\cdot 10^{-4}m)=1.48 m/s$

b) $3.0\cdot 10^{-5} J$

The fly's maximum kinetic energy is given by

$K=\frac{1}{2}mv_{max}^2$

where

$m=0.0270 g=2.7\cdot 10^{-5} kg$ is the mass of the fly

$v_{max}=1.48 m/s$ is the maximum speed

Substituting into the equation, we find

$K=\frac{1}{2}(2.7\cdot 10^{-5}kg)(1.48 m/s)^2=3.0\cdot 10^{-5} J$

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3 years ago