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Alexus [3.1K]
3 years ago
5

A 1200 kg car is travelling west at 45 m/s. What is the momentum of the car?

Physics
1 answer:
ohaa [14]3 years ago
8 0

Answer:

<h2>54,000 kg.m/s</h2>

Explanation:

The momentum of an object can be found by using the formula

momentum = mass × velocity

From the question we have

momentum = 1200 × 45

We have the final answer as

<h3>54,000 kg.m/s</h3>

Hope this helps you

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49. A block is pushed across a horizontal surface with a
nata0808 [166]

Answer:

(a) 37.5 kg

(b) 4

Explanation:

Force, F = 150 N

kinetic friction coefficient = 0.15

(a) acceleration, a = 2.53 m/s^2

According to the newton's second law

Net force = mass x acceleration

F - friction force = m a

150 - 0.15 x m g = m a

150 = m (2.53 + 0.15 x 9.8)

m = 37.5 kg

(b) As the block moves with the constant speed so the applied force becomes the friction force.

F = \mu m g \\\\150 = \mu\times 37.5\\\\\mu = 4

8 0
3 years ago
Brainliest if correct Question 1 of 10
Art [367]

Answer:

B

Explanation:

hope this helps you

4 0
2 years ago
Si se deja caer un carrito de una pista de coches sin friccion y su altura inicial es de 1.4 metros, cual es la velocidad maxima
Svet_ta [14]

Answer:

5.241\ \text{m/s}

Explanation:

m = Masa del coche

g = Aceleración debida a la gravedad = 9.81\ \text{m/s}^2

h = Altura = 1.4\ \text{m}

v = Velocidad del automóvil en la parte inferior de la pista

Aquí asumimos que el automóvil desciende verticalmente. La energía potencial del automóvil se completará convertida en energía cinética en la parte inferior de la pista ya que no hay pérdida de energía.

mgh=\dfrac{1}{2}mv^2\\\Rightarrow v=\sqrt{2gh}\\\Rightarrow v=\sqrt{2\times 9.81\times 1.4}\\\Rightarrow v=5.241\ \text{m/s}

La velocidad máxima que puede alcanzar el coche es 5.241\ \text{m/s}.

8 0
3 years ago
Find the acceleration that can result from a net force of 20 N exerted on a 2.8-kg
vladimir2022 [97]
Force=mass*acceleration
F=ma

20=2.8a

a=20/2.8

a=7.14 m/s^2
6 0
3 years ago
determine the magnitude and direction of the resultant for a combination of the vectors A: 10.1m, 60 degrees B: 7.3m, 275 degree
quester [9]

Answer:

5.87 m, 75.5°

Explanation:

Let's say C is the resultant vector.

The x component is the sum of the x components of A and B.

Cx = Ax + Bx

Cx = 10.1 cos 60° + 7.3 cos 275°

Cx = 5.69

The y component is the sum of the y components of A and B.

Cy = Ay + By

Cy = 10.1 sin 60° + 7.3 sin 275°

Cy = 1.47

The magnitude is found with Pythagorean theorem, and the angle is found with trigonometry.

C² = Cx² + Cy²

C² = 5.69² + 1.47²

C = 5.87

θ = atan(Cy / Cx)

θ = atan(5.69 / 1.47)

θ = 75.5°

5 0
3 years ago
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