Let’s call the speed of the slower car S, then the speed of the other is S+10mph.
At 5pm they have been travelling for 3 hours. The slower car travels a distance 3S and the faster one 3(S+10).
But the two distances must add up to 240 miles so 3S+3(S+10)=240, 3S+3S+30=240, 6S=210, S=35 mph. The faster car’s speed is 45mph. We can see that 3S is the same distance as 3x, so x=S=35 mph, and the distance the faster car travels is 3×45=135 miles.
Judging by the question I noticed that I can simplify the equation 3x-x+2=12 by one step.
The outcome of simplification should be 2x+2=12.
Next you must subtract 2 from both sides to isolate the x. The new equation should be 2x = 10.
Lastly you must divide both sides by 2, the answer you should get is x=5, D.
Answer:
y=1
Step-by-step explanation:
6=2(y+2)
Divide each side by 2
6/2=2/2(y+2)
3 = y+2
Subtract 2 from each side
3-2 = y+2-2
1 = y
Answer:
(x, y) ⇒ (½x, ½y)
(x, y) ⇒ (x + 7, y + 7)
Step-by-step explanation:
each x value of P'Q'R' is half of the x value for PQR
each y value of P'Q'R' is half of the y value for PQR
each x value of P"Q"R" is seven units to the right of the x value for P'Q'R'
each y value of P"Q"R" is seven units above the y value for P'Q'R'
The correct question in the attached figure
we know that
applying the law of sines
g/sinG=k/sinK
g=3 units
G=30°
k=4 units
K=?
so
g/sinG=k/sinK------> g*sinK=k*sinG-----> sinK=k*sinG/g
sinK=4*sin 30°/3-----> 2/3
K=arc sin(2/3)-------> K=41.81°
case 1)for angle K=41.81°the sum of the angles (H +G+K)=180°
H=180-(G+K)------> 180-(30+41.81)--------> H=108.19°
h/sinH=g/sinG-------> h=g*sinH/sinG------> h=3*sin 108.19°/sin 30°
h=5.70 units
case 2)for angle K=180°-
41.81°---------> K=138.19°
the sum of the angles (H +G+K)=180°
H=180-(G+K)------> 180-(30+138.19)--------> H=11.81°
h/sinH=g/sinG-------> h=g*sinH/sinG------> h=3*sin 11.81°/sin 30°
h=1.2 units
therefore
the answer is the option
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A. 1.2 or 5.7</span>