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Advocard [28]
3 years ago
12

1 2 3 4 5 6 7 8 9 10TIME REMAINING53:56A scientist told his student assistants that he had sorted groups of mice by their intell

igence and asked the assistants to assess the groups’ maze-solving abilities. The scientist had not actually sorted the mice by intelligence. The students rated the ""highest intelligence"" group of mice as the best maze solvers and the ""lowest intelligence"" group as the worst maze solvers. What was the scientist trying to demonstrate by doing this experiment?Experimental subjects should never be put into groups.Mice should not be judged by their intelligence.Higher intelligence mice are better maze solvers.People can introduce their own biases into an experiment.
Chemistry
1 answer:
Gekata [30.6K]3 years ago
4 0

Answer:

People can introduce their own biases into an experiment.

Explanation:

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When 2.50 g of an unknown weak acid (ha) with a molar mass of 85.0 g/mol is dissolved in 250.0 g of water, the freezing point of
baherus [9]
When dT = Kf * molality * i
                = Kf*m*i
and when molality = (no of moles of solute) / Kg of solvent
                               = 2.5g /250g x 1 mol /85 g x1000g/kg
                               =0.1176 molal
and Kf for water = - 1.86 and dT = -0.255
by substitution 
0.255 = 1.86* 0.1176 * i
∴ i = 1.166
when the degree of dissociation formula is: when n=2 and  i = 1.166
a= i-1/n-1 = (1.166-1)/(2-1) = 0.359 by substitution by a and c(molality) in K formula
∴K = Ca^2/(1-a)
     = (0.1176 * 0.359)^2 / (1-0.359)
     = 2.8x10^-3



5 0
3 years ago
A 8.00g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of
Ne4ueva [31]

Answer:

C3H6.

Explanation:

Data obtained from the question:

Mass of the compound = 8g

Mass of CO2 = 24.01g

Mass of H2O = 13.10g

Next, we shall determine the mass of C, H and O present in the compound. This is illustrated below:

Molar Mass of CO2 = 12 + (2x16) = 44g/mol

Molar Mass of H2O = (2x1) + 16 = 18g/mol

Mass of C in compound = Mass of C/Molar Mass of CO2 x 24.01

=> 12/44 x 24.01 = 6.5g

Mass of H in the compound = Mass of H/Molar Mass of H2O x 13.1

=> 2x1/18 x 13.1 = 1.5g

Mass of O in the compound = Mass of compound – (mass of C + Mass of H)

=> 8 – (6.5 + 1.5) = 0

Next, we shall determine the empirical formula of the compound. This is illustrated below:

C = 6.5g

H = 1.

Divide by their molar mass

C = 6.5/12 = 0.54

H = 1.4/1 = 1.

Divide by the smallest

C = 0.54/0.54 = 1

H = 1/0.54 = 2

Therefore, the empirical formula is CH2

Finally, we shall determine the molecular formula as follow:

The molecular formula of a compound is a multiple of the empirical formula.

Molecular formula = [CH2]n

[CH2]n = 44

[12 + (2x1)]n = 44

14n = 44

Divide both side by 14

n = 44/14

n = 3

Molecular formula = [CH2]n = [CH2]3 = C3H6

Therefore, the molecular formula of the compound is C3H6

4 0
3 years ago
Anything in red is the question
solmaris [256]

Answer:

<em />

  • <em>19. C₂H₂, HF, and H₂O₂ are molecular compounds</em>

<em />

  • <em>20. The formula is CuSO₄. 5H₂O</em>

Explanation:

<u><em>Question 19.</em></u>

The three the chemical formulae in red, C₂H₂, HF, and H₂O₂, represent compounds because a compound is the chemical union of two or more atoms of different kind.

The chemical union is done either by ionic bonds or covalent bonds.

C, H, F, and O are all non-metal elements. Non-metals combine each other through covalent bonds, which is the bond in which electrons are shared to complete the valence shell. Ionic bonds are formed by the electrostatic atraction between ions of different charge and is typical of the bond between a metal and a non-metal.

Thus, all the bonds are covalent and the compounds are molecular compounds.

<em></em>

<u><em>Question 20. </em></u>

<em></em>

You can determine the chemical formula using the molar masses of both Copper(II) sulfate and water.

  • Molar mass of copper(II) sulfate: 159.609 g/mol
  • Molar mass of water: 18.015 g/mol

Call n the number of water molecules in the molecular formula:

  • CuSO₄ . nH₂O

The ratio of water to copper(II) sulfate is:

  • n × molar mass of water / molar mass of the compound
  • n × 18.015 / (n × 18.015 + 159.609) = 36%
  • 18.015n = 0.36(18.015n + 159.609)
  • 18.015n = 6.4854n + 57.45924
  • 11.5296n = 57.45924
  • n = 4.9836 ≈ 5

Therefore, the formula of the hydrate contains 5 molecules of water and it is CuSO₄.5H₂O.

8 0
3 years ago
A piece of metal weighing 59.047 g was heated to 85.2°C and then put into 100.000 g of
balu736 [363]
Dayumm you failing dawg
8 0
3 years ago
PLEASE PLEASE HELP
Eva8 [605]
Try googleing it that is how i got some of mine

8 0
3 years ago
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