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SVETLANKA909090 [29]
3 years ago
11

pls answer asap For exercises 13-16, write an equation and find the measure of the angle labeled x, without measuring.

Mathematics
1 answer:
kvasek [131]3 years ago
5 0

Answer:

see explanation

Step-by-step explanation:

13

The 2 angles form a straight line and sum to 180° , that is

x + 30 = 180 ( subtract 30 from both sides )

x = 150

14

Similarly

x + 125 = 180 ( subtract125 from both sides )

x = 55

15

The 2 angles form a right angle, then

x + 27 = 90 ( subtract 27 from both sides )

x = 63

16

The 2 angles form a complete revolution of 360° , then

x + 35 = 360 ( subtract 35 from both sides )

x = 325

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Answer:

connect C and E with a straightedge

Step-by-step explanation:

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3 years ago
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What is the domain of the function f(x) = + 5?
Greeley [361]

Answer:

The domain of the function is:

\mathrm{Domain\:of\:}\:\sqrt{x+5}\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\ge \:-5\:\\ \:\mathrm{Interval\:Notation:}&\:[-5,\:\infty \:)\end{bmatrix}

Step-by-step explanation:

Given the function

f\left(x\right)\:=\sqrt{x+5}

We know that the domain of a function is the set of input or argument values for which the function is real and defined.

From the function, it is clear that for the values x<-5, the function becomes undefined.

For example, for x=-6

√x+5 = √-6+5 = √-1 which is undefined

and for x=-5

√x+5 = √5+5 = √0 which is defined

Thus, the domain of the function is:

\mathrm{Domain\:of\:}\:\sqrt{x+5}\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\ge \:-5\:\\ \:\mathrm{Interval\:Notation:}&\:[-5,\:\infty \:)\end{bmatrix}

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3 years ago
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What is the slope of the line shown?
KATRIN_1 [288]

Answer: We can't answer Because we cannot see it

Step-by-step explanation:

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3 years ago
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Find the value of x
baherus [9]

Answer: x=58

Step-by-step explanation:

We know that the entire angle equals 360 degrees

Let’s subtract 293 from 360

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Then let’s subtract 44 from 67 to get (x-35)

67 - 44 = 23

We now know that 23 = (x - 35), so let’s write and solve the equation for it

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3 0
4 years ago
Find the midpoint of the line segment that joins points P(-4,3) and Q(9,14)?
k0ka [10]

Given the following points:

Point P: (-4, 3)

Point Q: (9, 14)

To be able to find the midpoint of the line segment, we will be using the following formula:

\text{ Midpoint = }\frac{x_1+x_2}{2},\frac{y_1+y_2_{}}{2}

We get,

\text{ Midpoint = }\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\text{= }\frac{(-4)+(9)_{}}{2},\frac{3_{}+14_{}}{2}\text{ = }\frac{5}{2},\frac{17}{2}

Therefore, the midpoint of the line segment is 5/2, 17/2.

7 0
1 year ago
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