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3 years ago

15

PLSPLSPLSPLSPLS HELP

1 answer:

Alex17521 [72]3 years ago

7 0

I'll get back to you on it.

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Can you help me on this?

vagabundo [1.1K]

.......,ok first,WHAT THE WORLD THIS THAT!? And this may be how bread formed

4 0

4 years ago

Which statement best compares the energy involved in melting with the energy involved in boiling for a given liquid?

Nana76 [90]

Answer:

Energy is added to the particles in each change, but boiling requires more energy than melting because the attractions must be completely overcome.

7 0

3 years ago

The combustion of propane (C 3H 8) in the presence of excess oxygen yields CO 2 and H 2O: C 3H 8 (g) + 5O 2 (g) → 3CO 2 (g) + 4H

professor190 [17]

Answer:

1.5 mol of CO₂

Explanation:

Use the mole ratio to find how many moles of CO₂ are produced from the reaction.

For every 5 moles of O₂, three moles of CO₂ is produced.

2.5 mol O₂ × 3 mol CO₂ ÷ 5 mol O₂

= 2.5 mol O₂ × 0.6

= 1.5 mol CO₂

When 2.5 mol of O₂ is consumed in the reaction, 1.5 mol of CO₂ is produced.

Hope that helps.

8 0

4 years ago

A solid weak acid is weighed, dissolved in water and diluted to exactly 50.00 ml. 25.00 ml of the solution is taken out and is t

Artist 52 [7]

Answer:

pKa = 3.51

Explanation:

The titration of acid solution with NaOH can be illustrated as:

$AH + NaOH \to NaA + H_2O$

Given that:

Volume of acid solution $(V_1) = 25 \ mL$

Volume of NaOH $(V_2) = 18.8 \ mL$

Molarity of acid solution $(M_1) = ???$

Molarity of NaOH $(M_2) = 0.10 \ M$

For Neutralization reaction:

$M_1V_1 = M_2V_2$

Making $M_1$ the subject of the formula; we have:

$M_1 = \frac{M_2V_2}{V_1}$

$M_1 = \frac{0.10*18.8}{25}$

$M_1 =0.0752 \ M$

However; since the number of moles of NaA formed is equal to the number of moles of NaOH used : Then :

$M_2V_2 = 0.10 *18.8 = 1.88 \ mm$

Total Volume after titration = ( 25 + 18.8 ) m

= 43.8 mL

Molarity of salt (NaA ) solution = $\frac{number \ of \ moles}{Volume \ (mL)}$

= $\frac{1.88}{43.8}$

= 0.0429 M

After mixing the two solution ; the volume of half neutralize solution is = 25 mL + 43.8 mL

= 68.8 mL

Molarity of NaA before mixing $M_1 = 0.0429 \ M$

Volume $(V_1) = 43.8 \ mL$

Molarity of NaA after mixing $M_2 = ???$

Volume $(V_2 ) = 68.8 \ mL$

∴

$M_2 = \frac{M_1*V_1}{V_2} \\ \\ M_2 = \frac{0.0429*43.1}{68.8} \\ \\ M_2 = 0.0273 \ M$

Molarity of acid before mixing = 0.0725 M

Volume = 25 mL

Molarity of acid after mixing = $\frac{0.0752*25}{68.8}$

= 0.0273 M

Since this is a buffer solution ; then using Henderson Hasselbalch Equation

$pH = pKa + log \frac{[salt]}{[acid]}$

$3.51= pKa + log \frac{[0.0273]}{[0.0273]} \\ \\ 3.51= pKa + log \ 1 \\ \\ 3.51= pKa + 0 \\ \\ pKa = 3.51$

4 0

4 years ago

Identify the weakest bond. identify the weakest bond. triple covalent bond single covalent bond double covalent bond all of the

Oliga [24]

The weakest bond is a single covalent bond.

5 0

3 years ago