Question

Compound A reacts with Compound B to form only one product, Compound C, and it's known the usual percent yield of C in this reaction is 40%. Suppose 10.0 g of A are reacted with excess Compound B, and 6.4 g of Compound C are successfully isolated at the end of the reaction.

Answer 1

Given :

Compound A reacts with Compound B to form only one product, Compound C.

The usual percent yield of C in this reaction is 40%.

10.0 g of A are reacted with excess Compound B, and 6.4 g of Compound C

To Find :

The theoretical yield of C.

Solution :

We know, % yield is given by :

$\%\ yield = \dfrac{actual\ yield}{theoretical\ yield }\times 100$

Putting given values , we get :

$40 = \dfrac{6.4}{theoretical\ yield }\times 100\\\\theoretical\ yield=\dfrac{6.4\times 100}{40}\\\\theoretical\ yield=16\ g$

Therefore, theoretical yield of C is 16 g.

Hence, this is the required solution.