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3 years ago

11

Identify the weakest bond. identify the weakest bond. triple covalent bond single covalent bond double covalent bond all of the

above bonds are the same strength

1 answer:

Oliga [24]3 years ago

5 0

The weakest bond is a single covalent bond.

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What are the units of molality? A. mol/kg B. g/mol C. mol/L D. kg/mol

Serhud [2]

Answer: A.mol/kg

The SI (international system) unit for molality is mol / kg, or solute moles per kg of peptides. A solution with a molality of 1 mol / kg is often described as "1 molal" or "1 m".

5 0

3 years ago

Read 2 more answers

water is formed when 48g of oxygen combine with 6g of hydrogen. what mass of oxygen combines with 2g of hydrogen

Mariulka [41]

Answer:

16g of oxygen reacts with 2 g of hydrogen to form 18g of Water

6 0

2 years ago

Please help asap thank you.

Aleks [24]

Answer:

a)0.816g/l

b)0.241g/l

8 0

3 years ago

If 30 ml of water containing 15 mg of salicylate is extracted with 30 ml of chloroform, 2.59 mg of salicylate remains in the wat

In-s [12.5K]

Answer:

Distribution coefficient: 4.79

Explanation:

Distribution coefficient is the ratio between equilibrium concentration of non-aqueous phase and aqueous phase where both solvents are inmiscible. The equation for the problem is:

Distribution coefficient: Concentration in chloroform / Concentration in Water

<em>Concentration in water: 2.59mg / 30mL = 0.08633mg/mL</em>

<em>Concentration in chloroform: (15mg-2.59mg) / 30mL = 0.4137mg/mL</em>

<em />

Distribution coefficient: 0.4137mg/mL / 0.08633mg/mL

<h3>Distribution coefficient: 4.79</h3>

8 0

3 years ago

What is the relationship between atmospheric pressure and the density of gas particles in an area of increasing pressure? As air

Marina86 [1]

We need to know the relationship between atmospheric pressure and the density of gas particles in an area of increasing pressure.

The relationship is: As air pressure in an area increases, the density of the gas particles in that area increases.

For any gaseous substance, density of gas is directly proportional to pressure of gas.

This can be explained from idial gas edquation:

PV=nRT

PV= $\frac{w}{M}$ RT [where, w= mass of substance, M=molar mass of substance]

PM= $\frac{w}{V}$ RT

PM=dRT [where, d=density of thesubstance]

So, for a particular gaseous substance (whose molar mass is known), at particular temperature, pressure is directly related to density of gaseous substance.

Therefore, as air pressure in an area increases, the density of the gas particles in that area increases.

3 0

3 years ago