Answer:
a*(20-a)
Step-by-step explanation:
Let's assume that the length of the garden is a the width is b and the area is s.
b = 40/2 - a = 20-a
s =a*(20-a)=-a^2+20a=-(a-10)^2+100
then,
when a=10, max(-(a-10)^2) =0, max(s)=100
Answer:
The answer is t=1/9
Step-by-step explanation:
If we substitute sqrt(t) = u, then we can write the equation as 3u^2+5u-2=0.
Using the <em>quadratic formula</em>, we can solve that <u>u = 1/3 and u = -2.</u>
We can go back to our original substitution and say that <em>sqrt(t) = 1/3</em>. The sqrt(t) can not be -2 because a <u>square root can not be negative.</u>
If we solve the equation sqrt(t) = 1/3, we get that t=1/9.
Reaches every cell in the body
It might be 4 and 8 because 4 is one-half of 8 and when you multiply them you get 32
