B.
its the only one with ozone in the reaction O₃
Answer:
43%
Explanation:
As the problem says that the antimony has only two isotopes, lets call each isotope the following:
x=abundance of isotope 121Sb
1-x=abundance of isotope 123Sb
And
Atomic weight of antimony = (isotopic mass of 121Sb*x)+(isotopic mass of 123Sb*(1-x))
Replacing values we have:
Solving for x:
it means that the abundance of the isotope 121Sb is 57% and the abundance of isotope 123Sb is 43%
Answer:
2.0 g Na
Explanation:
Stoichiometry.
8.4g sodium hydrogen citrate x (1 mol sodium hydrogen citrate / 192 g sodium hydrogen citrate) x (2 mol Na/1 mol sodium hydrogen citrate) x (23g Na/1 mol Na)
^write it out it makes more sense that way