Answer:
2Cs+Sr(CrO4)-->Cs2(CrO4)+Sr
Explanation:
just set them equal, only value that changed was the amount of cesium(Cs)
Plssssssssss the answer is... you
Thewater of hydration x in narceine. xH₂O is 3
<h3>
What is Water of Hydration?</h3>
- In chemistry, water molecules found inside crystals are referred to as "water of crystallization" or "water of hydration." When crystals are formed from aqueous solutions, water is frequently included.
- The entire mass of water in a substance at a specific temperature is sometimes referred to as water of hydration, and it is typically present in a stoichiometric ratio.
- The term "water of crystallization" has historically been used to describe water that is not physically linked to the metal cation but is present in the crystalline structure of a metal complex or salt.
- Many chemicals include water molecules in their crystalline structures when they crystallize from water or solvents that contain water. Heating a sample usually removes the water of crystallization, but the crystalline qualities are frequently lost.
Given that hydrate is 10.8% by mass
molar mass = 499.52 g/mol
calculating the amount of water
mass of water = 
mass of water = 53.95 g
moles of water = 
moles of water =
= 3
then the water of hydration x in narceine. xH₂O is 3
To learn more about water of hydration with the given link brainly.com/question/4355575
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Answer:
, Kp = 0.08967
, Kp = 2.3×10³⁰
Explanation:
The relation between Kp and Kc is given below:

Where,
Kp is the pressure equilibrium constant
Kc is the molar equilibrium constant
R is gas constant
T is the temperature in Kelvins
Δn = (No. of moles of gaseous products)-(No. of moles of gaseous reactants)
For the first equilibrium reaction:

Given: Kc = 2.2
Temperature = 299 K
R = 0.082057 L atm.mol⁻¹K⁻¹
Δn = (2)-(2+1) = -1
Thus, Kp is:

<u>Kp = 0.08967 </u>
For the second equilibrium reaction:

Given: Kc = 2.3×10³⁰
Temperature = 299 K
R = 0.082057 L atm.mol⁻¹K⁻¹
Δn = (2)-(2) = 0
Thus, Kp is:

<u>Kp = 2.3×10³⁰</u>