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hjlf
3 years ago
15

Fusion and fission reactions are both nuclear reactions that can be used to produce energy. However, while fission reactions are

observed as a natural decay route for some nuclei on Earth, fusion is not seen under typical ambient planetary conditions. More extreme conditions, like are present in stars, are typically necessary for fusion to occur on a large scale.1. Which of the answers below correctly describes the reasoning for this difference?A) Both fusion and fission reactions are initiated by neutron addition to the nuclei involved in the reaction. However, fusion reactions, unlike fission reactions, do not produce large amounts of extra neutrons to propagate the chain reaction needed to sustain a reaction at a high rate.B) Both fusion and fission reactions require nuclear collisions. Fusion reactions involve smaller nuclei which collide less frequently with each other, causing a slower reaction. Fission reactions involve larger nuclei, making collisions more frequent, leading to faster reaction rates.C) Fusion reactions result in less energy released as heat than is seen in fission reactions. Because less heat is released there is less energy present in the reactants to overcome the large activation energy for these reactions. Fission reactions also have a large activation barrier, but the heat produced by these reactions is much greater, giving the nuclei the energy they need to complete the reaction.D) Fusion reactions have a larger barrier to reaction due to the repulsion forces required for two nuclei to come together. Because the nuclei are both positively charged, the repulsive force between the two has to be overcome for fusion to occur. Fission reactions do not involve nuclear collisions and therefore have a lower barrier to reaction.E. The binding energy per nucleon is much lower, on average, for atoms involved in fusion reactions. This means that the reactions are less energetically favorable, as binding energy per nucleon is a measure of stability. Because there is much less energetic driving force, the reaction rate is much slower overall, meaning that it is more difficult to observe under ambient conditions.
Chemistry
1 answer:
kipiarov [429]3 years ago
3 0

Answer:

I dont say bla bla bla

Explanation:

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2Cs+Sr(CrO4)-->Cs2(CrO4)+Sr

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Determine the number of miles of C in each sample​
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Narceine is a narcotic in opium that crystallizes from solution as a hydrate that contains 10.8 mass % water and has a molar mas
Leto [7]

Thewater of hydration x in narceine. xH₂O is 3

<h3>What is Water of Hydration?</h3>
  • In chemistry, water molecules found inside crystals are referred to as "water of crystallization" or "water of hydration." When crystals are formed from aqueous solutions, water is frequently included.
  • The entire mass of water in a substance at a specific temperature is sometimes referred to as water of hydration, and it is typically present in a stoichiometric ratio.
  • The term "water of crystallization" has historically been used to describe water that is not physically linked to the metal cation but is present in the crystalline structure of a metal complex or salt.
  • Many chemicals include water molecules in their crystalline structures when they crystallize from water or solvents that contain water. Heating a sample usually removes the water of crystallization, but the crystalline qualities are frequently lost.

Given that hydrate is 10.8% by mass

molar mass = 499.52 g/mol

calculating the amount of water

mass of water = \dfrac{10.8 \times 499.5}{100}

mass of water = 53.95 g

moles of water = \dfrac{mass}{molar mass}

moles of water = \dfrac{53.95}{18} = 3

then the water of hydration x in narceine. xH₂O is 3

To learn more about water of hydration with the given link brainly.com/question/4355575

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7 0
1 year ago
Calculate the equilibrium constant Kp for this reaction, given the following information (at 299 K ): 2NO(g)+Br2(g)⇌2NOBr(g)Kc=2
Travka [436]

Answer:

2NO_{(g)}+Br_2_{(g)}\rightleftharpoons2NOBr_{(g)} , Kp = 0.08967

2NO_{(g)}\rightleftharpoons N_2_{(g)}+O_2_{(g)} , Kp = 2.3×10³⁰

Explanation:

The relation between Kp and Kc is given below:

K_p= K_c\times (RT)^{\Delta n}

Where,

Kp is the pressure equilibrium constant

Kc is the molar equilibrium constant

R is gas constant

T is the temperature in Kelvins

Δn = (No. of moles of gaseous products)-(No. of moles of gaseous reactants)

For the first equilibrium reaction:

2NO_{(g)}+Br_2_{(g)}\rightleftharpoons2NOBr_{(g)}

Given: Kc = 2.2

Temperature = 299 K

R = 0.082057 L atm.mol⁻¹K⁻¹

Δn = (2)-(2+1) = -1

Thus, Kp is:

K_p= 2.2\times (0.082057\times 299)^{-1}

<u>Kp = 0.08967 </u>

For the second equilibrium reaction:

2NO_{(g)}\rightleftharpoons N_2_{(g)}+O_2_{(g)}

Given: Kc = 2.3×10³⁰

Temperature = 299 K

R = 0.082057 L atm.mol⁻¹K⁻¹

Δn = (2)-(2) = 0

Thus, Kp is:

K_p= 2.2\times (0.082057\times 299)^{0}

<u>Kp =  2.3×10³⁰</u>

3 0
3 years ago
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