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topjm [15]
3 years ago
15

Of all the visitors to a museum on Saturday, 18% were kids younger than 11 years old. In lowest terms, write the fraction of vis

itors to the museum who were younger than 11 years old.
Mathematics
1 answer:
Aleksandr-060686 [28]3 years ago
4 0
<h3>Answer:  9/50</h3>

Explanation:

Any percentage converts to that number over 100.

So 18% would convert to 18/100

We then reduce the fraction by dividing each part by the GCF 2

18/2 = 9

100/2 = 50

The fraction 18/100 fully reduces to 9/50

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What is the vertex of the absolute value function below?
Nonamiya [84]

Answer:

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4 0
2 years ago
Determine if there is a proportional relationship between the two quantities
Shalnov [3]

Answer:

The table a not represent a proportional relationship between the two quantities

The table b represent a proportional relationship between the two quantities

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form k=\frac{y}{x} or y=kx

<u><em>Verify each table</em></u>

<em>Table a</em>

Let

A ----> the independent variable or input value

B ----> the dependent variable or output value

the value of k will be

k=\frac{B}{A}

For A=35, B=92 ---> k=\frac{92}{35}=2.63

For A=23, B=80 ---> k=\frac{80}{23}=3.48

the values of k are different

therefore

There is no proportional relationship between the two quantities

<em>Table b</em>

Let

C ----> the independent variable or input value

D ----> the dependent variable or output value

the value of k will be

k=\frac{D}{C}

For C=20, D=8 ---> k=\frac{8}{20}=0.40

For C=12.5, D=5 ---> k=\frac{5}{12.5}=0.40

the values of k are equal

therefore

There is a proportional relationship between the two quantities

The linear equation is equal to

D=0.40C

7 0
3 years ago
Leslie is going to the state fair with her friends but can only stay for 3 hours. The event offers two different pricing structu
Cloud [144]
 The answer would be D. It would be $42 in the end if you picked D.
5 0
3 years ago
Your sample size is 10 and your confidence is 90%. What is your t-score?
PilotLPTM [1.2K]

Answer:

if you want a t*-value for a 90% confidence interval when you have 9 degrees of freedom, go to the bottom of the table, find the column for 90%, and intersect it with the row for df = 9. This gives you a t*–value of 1.833 (rounded).

Step-by-step explanation:

Hope this helps!

6 0
3 years ago
Coffee: A popular chain of cafes has been receiving online complaints about one store location. Regular customers complained tha
spin [16.1K]

Answer:

z=\frac{0.18 -0.1}{\sqrt{\frac{0.1(1-0.1)}{100}}}=2.67  

Step-by-step explanation:

1) Data given and notation

n=100 represent the random sample taken

X=18 represent the ounce cups of coffee that were underfilled

\hat p=\frac{18}{100}=0.18 estimated proportion of ounce cups of coffee that were underfilled

p_o=0.1 is the value that we want to test

\alpha represent the significance level  

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion it's higher than 0.1 or 10%:  

Null hypothesis:p\leq 0.1  

Alternative hypothesis:p > 0.1  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.18 -0.1}{\sqrt{\frac{0.1(1-0.1)}{100}}}=2.67  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level assumed for this case is \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a one right tailed test the p value would be:  

p_v =P(Z>2.67)=0.0037  

So the p value obtained was a very low value and using the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance thetrue proportion is not significanlty higher than 0.1 or 10% .  

5 0
4 years ago
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