It appears that you have a derivative and want to integrate...
dy/dx=1+3√x
y(x)=x+(2/3)x^(3/2)+C you are given that f(4)=25 so we can solve for the constant of integration...
y(4)=25=4+16/3+C
21=16/3+C
(63-16)/3=C
47/3=C so
f(x)=x+(2/3)x^(3/2)+47/3
f(x)=(3x+2x^(3/2)+47)/3
Average rate of change = change in y ÷ change in x
We already know the change in x because we are measuring the x values from -3 to 0.
change in x = 0-(-3) = 3
To find the change in y find the difference between the corresponding y-values when x=0 and when x=-3.
change in y = 0.5-2 = -1.5
average rate of change = -1.5/3 = -0.5
answer: -0.5
Answer:
4√2i , -4√2i.
Step-by-step explanation:
3x^2 + 64 = 2x^2/2
3x^2 + 64 = x^2
2x^2 + 64 = 0
2x^2 = -64
x^2 = -32
x = +/- √-32
x = +/- √16* -2
x = +/- 4√2 i.
