Answer:
The inverse of function
is ![\mathbf{f^{-1} (x)=\sqrt[5]{x}+7}](https://tex.z-dn.net/?f=%5Cmathbf%7Bf%5E%7B-1%7D%20%28x%29%3D%5Csqrt%5B5%5D%7Bx%7D%2B7%7D)
Option A is correct option.
Step-by-step explanation:
For the function
, Find ![f^{-1} (x)](https://tex.z-dn.net/?f=f%5E%7B-1%7D%20%28x%29)
For finding inverse of x,
First let:
![y=(x+7)^5](https://tex.z-dn.net/?f=y%3D%28x%2B7%29%5E5)
Now replace x with y and y with x
![x=(y+7)^5](https://tex.z-dn.net/?f=x%3D%28y%2B7%29%5E5)
Now, solve for y
Taking 5th square root on both sides
![\sqrt[5]{x}=\sqrt[5]{(y+7)^5}\\\sqrt[5]{x}=y+7\\=> y+7=\sqrt[5]{x}\\y=\sqrt[5]{x}-7](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%7D%3D%5Csqrt%5B5%5D%7B%28y%2B7%29%5E5%7D%5C%5C%5Csqrt%5B5%5D%7Bx%7D%3Dy%2B7%5C%5C%3D%3E%20y%2B7%3D%5Csqrt%5B5%5D%7Bx%7D%5C%5Cy%3D%5Csqrt%5B5%5D%7Bx%7D-7)
Now, replace y with ![f^{-1} (x)](https://tex.z-dn.net/?f=f%5E%7B-1%7D%20%28x%29)
![f^{-1} (x)=\sqrt[5]{x}+7](https://tex.z-dn.net/?f=f%5E%7B-1%7D%20%28x%29%3D%5Csqrt%5B5%5D%7Bx%7D%2B7)
So, the inverse of function
is ![\mathbf{f^{-1} (x)=\sqrt[5]{x}+7}](https://tex.z-dn.net/?f=%5Cmathbf%7Bf%5E%7B-1%7D%20%28x%29%3D%5Csqrt%5B5%5D%7Bx%7D%2B7%7D)
Option A is correct option.
Answer:
graph?
Step-by-step explanation:
<u>Answer</u>:
18 clips for $7.38 is the best value deal.
<u>Step-by-step explanation:</u>
An office is restocking office supplies. The table below shows the cost for the number of boxes of paperclips. We need to find what is the best value is.
To find the best value for money we can check the price of each paperclip.
To check the price of each paper clip we can use the following formula:
![\text{Price of each paper clip} =\frac{\text { price of the box }} {{\text {number of clips in the box }}}](https://tex.z-dn.net/?f=%5Ctext%7BPrice%20of%20each%20paper%20clip%7D%20%3D%5Cfrac%7B%5Ctext%20%7B%20price%20of%20the%20box%20%7D%7D%20%7B%7B%5Ctext%20%7Bnumber%20of%20clips%20in%20the%20box%20%7D%7D%7D)
Now we can calculate the best value deal as follows:
![\text{Price of each clip is box 1}=\frac{7.38}{18}=0.41$](https://tex.z-dn.net/?f=%5Ctext%7BPrice%20of%20each%20clip%20is%20box%201%7D%3D%5Cfrac%7B7.38%7D%7B18%7D%3D0.41%24)
![\text{Price of each clip is box 2}=\frac{15.39}{27}=0.57$](https://tex.z-dn.net/?f=%5Ctext%7BPrice%20of%20each%20clip%20is%20box%202%7D%3D%5Cfrac%7B15.39%7D%7B27%7D%3D0.57%24)
![\text{Price of each clip is box 3}=\frac{13.50}{30}=0.45$](https://tex.z-dn.net/?f=%5Ctext%7BPrice%20of%20each%20clip%20is%20box%203%7D%3D%5Cfrac%7B13.50%7D%7B30%7D%3D0.45%24)
![\text{Price of each clip is box 4}=\frac{18.36}{36}=0.51$](https://tex.z-dn.net/?f=%5Ctext%7BPrice%20of%20each%20clip%20is%20box%204%7D%3D%5Cfrac%7B18.36%7D%7B36%7D%3D0.51%24)
![\text{Price of each clip is box 5}=\frac{18.80}{40}=0.47$](https://tex.z-dn.net/?f=%5Ctext%7BPrice%20of%20each%20clip%20is%20box%205%7D%3D%5Cfrac%7B18.80%7D%7B40%7D%3D0.47%24)
So, from looking at the prices of each paperclip we can conclude that the 18 clips for $7.38 is the best value deal.
Answer:
Step-by-step explanation:
I the given problem, there should be 32 in place of 35.
![F = \frac{9}{5} C + 32 \\ F - 32= \frac{9}{5} C \\ 5( F - 32)= 9 C \\ \frac{5}{9} ( F - 32)=C \\ \\ \huge \red{ \boxed{ C = \frac{5}{9} ( F - 32)}}](https://tex.z-dn.net/?f=F%20%3D%20%20%5Cfrac%7B9%7D%7B5%7D%20%20C%20%2B%2032%20%5C%5C%20F%20%20-%2032%3D%20%20%5Cfrac%7B9%7D%7B5%7D%20%20C%20%5C%5C%205%28%20F%20%20-%2032%29%3D%20%209%20%20C%20%5C%5C%20%20%5Cfrac%7B5%7D%7B9%7D%20%28%20F%20%20-%2032%29%3DC%20%5C%5C%20%20%5C%5C%20%5Chuge%20%5Cred%7B%20%5Cboxed%7B%20C%20%3D%20%5Cfrac%7B5%7D%7B9%7D%20%28%20F%20%20-%2032%29%7D%7D)