Explanation:
Let us assume that the given data is as follows.
mass of barium acetate = 2.19 g
volume = 150 ml = 0.150 L (as 1 L = 1000 ml)
concentration of the aqueous solution = 0.10 M
Therefore, the reaction equation will be as follows.

Hence, moles of
=
.......... (1)
As, No. of moles =
Hence, moles of
will be calculated as follows.
No. of moles =
=
(molar mass of
is 255.415 g/mol)
= 
Moles of
= 
= 0.01715 mol
Hence, final molarity will be as follows.
Molarity = 
= 
= 0.114 M
Thus, we can conclude that final molarity of barium cation in the solution is 0.114 M.
Use a proportion ...
<span>100.0g - 38.67g - 13.86g = 47.47g Oxygen </span>
<span>285.0 mg = 0.285g </span>
<span>47.47/100 = x/0.285g </span>
<span>x = ( 47.47/100) X 0.285g </span>
The anserr is c that what i think
Answer:
Okay the Answers are top to bottom.
5, 4, 1, 3, 2
Explanation: