a) The car’s speed just after leaving the icy portion of the road is the first part
We have s = ut +
Here s = 130 m, a = -1.2 
, u = 76 mile/hr = 33.975 m/s
After 14.72 seconds cars speed is given by v =u +at
u = 33.975m/s, a = -1.2
v = 33.975-1.2*14.72 = 16.31 m/s
So velocity of car on leaving icy surface = 16.31 m/s
b) Time taken after icy surface
0 = 16.31 - 7.10*t
t = 2.23 seconds
Distance traveled during this time
Total distance traveled = 130+18.74 = 148.74 m
c) Total time taken = 14.72+2.23=16.95 seconds
Answer:
Over Here
Explanation:
Newton's second law of motion can be formally stated as follows: The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.
I might have did mistake with calculations but this is how you should do.
<h2>
Answer: Toward the center of the circle.</h2>
This situation is characteristic of the uniform circular motion , in which the movement of a body describes a circumference of a given radius with constant speed.
However, in this movement the velocity has a constant magnitude, but its direction varies continuously.
Let's say 
is the velocity vector, whose direction is perpendicular to the radius 
of the trajectory, therefore
the acceleration 
is directed toward the center of the circumference.
