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grigory [225]
3 years ago
13

1.) How much potential energy does an object with a mass of 3 kg have on top of a stand 12 meters

Physics
1 answer:
Elena-2011 [213]3 years ago
7 0

Answer:

<h2>352.8 Joules</h2>

Explanation:

The potential energy of a body can be found by using the formula

PE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 9.8 m/s²

From the question we have

PE = 3 × 9.8 × 12

We have the final answer as

<h3>352.8 J</h3>

Hope this helps you

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Vitek1552 [10]
C, due to stuff and whatnot
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A 6 kg object falls 10 m. The object is attached mechanically to a paddle-wheel which rotates as the object falls. The paddle-wh
maksim [4K]

Answer:16.234^{\circ}C

Explanation:

Given

Mass of object (m)=6 kg

falling height(h)=10 m

mass of water(m_w)=600 gm

temperature of water =15

specific heat of water =4.186 j/g-^{\circ}C

Let T be the Final Temperature of water

Here Object Potential Energy is converted into Heat energy which will be absorbed by water

Potential Energy(P.E.)=mgh=6\times 9.81\times 10=588.6 J

Heat supplied=m_wc(\Delta T)

H.E.=600\times 4.186\times (T-16)

588.6=2511.6\times (T-16)

T-16=0.234

T=16.234^{\circ}C

This is not an efficient way of heating water as there is only0.234^{\circ}Cincrease in temperature.

5 0
3 years ago
What is the area of 12 1/2 and 17 1/5
jonny [76]
215

I am assuming that those are the width and length. So to find area all you have to do is multiply the two because lw = a. 12 1/2*17 1/5 = 215

25/2*86/5 = 2150/10 = 215
3 0
3 years ago
Which of the following correctly describe electric field lines?
Xelga [282]

-- Electric field lines DO never cross.  <em>(A) </em>

-- Electric field lines that are close together DO indicate a stronger electric field. <em>(B) </em>

-- Electric field lines DO not affect the charge that created them.  <em>(C)</em>

-- Electric field lines DON'T begin on north poles and end on south poles.  North and South "poles" are the way we talk about magnets, not electric charges.

6 0
3 years ago
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A 15kg dog jumps out of a 40kg canoe. If the dogs velocity is 1.2m/s, what is the velocity of the canoe?
vivado [14]

Answer:

v = -0.45 m/s

Explanation:

Assuming the canoe was initially at rest with momentum L = 0

and that the dog's velocity is in the positive direction

conservation of momentum

0 = 15(1.2) + 40v

v = -0.45 m/s

6 0
3 years ago
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