It most common to round to the hundredths place, this is two spaces after the decimal.
So look two spaces right - 0.17. If the third digit (in this case 6) is higher than 5 you round the number up if its not, keep it the same.
"6" is greater than five, so round it to about (or approximately) 0.18.
Do you have to keep going or only just one more number it seems to be going by 2’s 4,6,8,10,12 but I’m a little confused since it says it’s 9th grade work
Answer: (-2y+3)(y+11)
Step-by-step explanation:
33 is 3×11 so expect something like
(y+3)(y+11) = y^2+14y+33
leading term has coefficient -2 so
one factor is like (-2y+__)
Try (-2y+3)(y+11) = -2y^2-19y+33
which happens to be the answer
The answer if i’m not wrong would be r 3-2 equals 1 which is r.
You add up all of the Frequencies together (to get 50)
The number 6 was rolled 9 times. So that makes it 9/50.
9/50 -> .18 or 18%
Does that help?
