Answer:
Yes, it will reach or exceed 141 degree F
Step-by-step explanation:
Given equation that shows the temperature T in degrees Fahrenheit x minutes after the machine is put into operation is,

Suppose T = 141°F,



Since, a quadratic equation
has,
Real roots,
If Discriminant, 
Imaginary roots,
If D < 0,
Since, 
Thus, roots of -0.005x² + 0.45x + 125 are real.
Hence, the temperature can reach or exceed 141 degree F.
Answer:
212 children, and 265 adults
Step-by-step explanation:
To find the number of children and adults, we can set up a systems of equations.
x= number of children
y= number of adults
Equation 1: Price
1.50x+2.25y=914.25
Equation 2: Total number of people
x+y=477
Now, let's solve the equation using substitution.
Rearrange the second equation to solve for one variable.
x+y=477
x=477-y
Now plug x equals into the first equation, and solve for y.
1.50x+2.25y=914.25
1.50(477-y)+2.25y=914.25
715.5-1.50y+2.25y=914.25
715.5+0.75y=914.25
0.75y=198.75
y=265
We just solved for the number of adults. Now let's plug y equals into the second equation to find the number of children.
x+y=477
x+265=477
x=212
Answer: Okay so do 3x7.5 then 3x11.5 then 7.5x11.5 then add it up and you should get 143.25
The volume of soup in the cylindrical can is 100.48 inches cube.
<h3>How to find the volume of a cylindrical can?</h3>
We have to find the volume of the soup in a cylindrical can of height 8 inches and 4 inches across the lid.
The volume of the soup is the volume of the cylindrical can.
Therefore,
volume of the cylindrical can = πr²h
where
- r = radius of the cylinder
- h = height of the cylinder
Therefore,
h = 8 inches
r = 4 / 2 = 2 inches
volume of the soup in the cylindrical can = πr²h
volume of the soup in the cylindrical can = π × 2² × 8
volume of the soup in the cylindrical can = π × 4 × 8
volume of the soup in the cylindrical can = 32π
Therefore,
volume of the soup in the cylindrical can = 32 × 3.14
volume of the soup in the cylindrical can = 100.48 inches³
learn more on volume here:brainly.com/question/23207959
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