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likoan [24]
2 years ago
13

The points (2a, – 4a + 3), (2b - 3, b) lie on the graph of the equation

Mathematics
2 answers:
vladimir2022 [97]2 years ago
8 0

Answer:

  • a = -2.5, b = 1

Step-by-step explanation:

<u>Given line:</u>

  • y = -3x - 2

<u>Points on the same line:</u>

  • (2a, -4a + 3) and (2b - 3, b)

<u>Substitute x and y values of both points into equation of the line and solve for a and b:</u>

  • -4a + 3 = -3(2a) - 2 ⇒ -4a + 3 = -6a - 2 ⇒ 6a - 4a = -2 - 3 ⇒ 2a = -5 ⇒ a = -2.5
  • b = -3(2b - 3) - 2 ⇒ b = -6b + 9 - 2 ⇒ b+ 6b = 7 ⇒ 7b = 7 ⇒ b = 1

CaHeK987 [17]2 years ago
8 0

Answer:

The points (2a, – 4a + 3), (2b - 3, b) lie on the graph of the equation y = -3x - 2

Now,

By substituting x and y with the value of the points, we get

- 4a + 3 =  - 3(2a) - 2 \\  - 4a + 3 =  - 6a - 2 \\ 6a - 4a =  - 3 - 2 \\ 2a =  - 5 \\ a =  \frac{( - 5)}{2}  \\  \boxed{a =  - 2.5}

\\ b =- 3(2b - 3) - 2 \\ b =  - 6b + 9 - 2 \\ b + 6b = 9 - 2 \\ 7b = 7 \\  b =  \frac{7}{7}  \\  \boxed{b = 1}

Therefore,

  • The value of a is <u>-2.5</u>.
  • The value of b is <u>1</u>.
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I assume you meant to say "independent", not "indecent", meaning we're looking for the constant term in the expansion. This happens for k such that

12 - 3k = 0   ===>   3k = 12   ===>   k = 4

which corresponds to the constant coefficient

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3 0
2 years ago
(05.05)
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Answer:

5

Step-by-step explanation:

The initial value is when x=0

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A cylinder has a radius of 10 M and a height of 8 AM what is the exact volume of the cylinder
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What 2 numbers add to get 2 and multiply to 4
rusak2 [61]
Factor 4
4=1 times 4
2 times 2
they don't add to 2
set up equation
x+y=2
xy=4

first equation, subtract x from both sides
y=2-x
subsitute for y
x(2-x)=4
distribute
2x-x^2=4
add x^2
2x=x^2+4
subtract 2x
0=x^2-2x+4
use quadratic formula which is
if you have ax^2+bx+c=0 then
x=\frac{ -b+/-\sqrt{b^{2}-4ac} }{2a} so

1x^2-2x+4=0
a=1
b=-2
c=4
x=\frac{ -(-2)+/-\sqrt{(-2)^{2}-4(1)(4)} }{2(1)}
x=\frac{ 2+/-\sqrt{4-16} }{2}
x=\frac{ 2+/-\sqrt{-12} }{2}
we have \sqrt{-12} and that doesn't give a real solution
therefor there are no real solutions
but if you want to solve fully
x=\frac{ 2+/-2\sqrt{-3} }{2}
i=\sqrt{-1}
x=\frac{ 2+/-2i\sqrt{3} }{2}
x=1+/-i\sqrt{3}
x=1-i\sqrt{3} or x=1+i\sqrt{3} (those are the 2 numbers)

 





6 0
3 years ago
Please Help Fast!!!!!​
Gnoma [55]
Hey I just saw this do u need Help Still or no my fault gang nobody helped you out at all
3 0
1 year ago
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