- Angle (θ) = 60°
- Force (F) = 20 N
- Distance (s) = 200 m
- Therefore, work done
- = Fs Cos θ
- = (20 × 200 × Cos 60°) J
- = (20 × 200 × 1/2) J
- = (20 × 100) J
- = 2000 J
<u>Answer</u><u>:</u>
<u>2</u><u>0</u><u>0</u><u>0</u><u> </u><u>J</u>
Hope you could get an idea from here.
Doubt clarification - use comment section.
Answer:
98m/s
Explanation:
Given parameters:
Time = 10s
Unknown:
Final speed = ?
Solution:
To solve this problem, we use the expression below;
v = u + gt
v is the final velocity
u is the initial velocity = 0m/s
g is the acceleration due to gravity = 9.8m/s²
t is the time
so;
v = 0 + 9.8 x 10 = 98m/s
Answer:
False
Explanation:
Because when you go through east
( +x axis ) then you go to west ( -x axis )
You will subtract -9 from +15
it's become +6
( I talk about the displacement not distance) ( West = - East )
I hope that it's a clear ") .
Answer : C. Pascal's principle.
Explaination : Pascal's principle (well-known as Pascal's law) states that if a closed container contains a fluid at rest, then a small change in pressure at one side of the fluid is transmitted to each and every part of the fluid and also to the walls of the container without any loss. In a hydraulic lift, we need the same mechanism to work and so we take the help of Pascal's principle.
Hence, the correct option is C. Pascal's principle.
Answer:
The answer to your question is:
a) h max = 529.7 m
b) t = 20.4 s
c) t = 20.6 s
Explanation:
a) h max = -(vo)² / 2g
= 100² / 2(9.81)
= 10000 / 19.62
= 509.7 m
total height = 509.7 + 20 = 529.7 m
b)
h = gt² / 2
t = √ 2h / g
t = √ 2(509.7)/9.81
t = √ 103.91
t = 10.19 s
total time = 2 x t = 2 x 10.19 = 20.4 s
c)
h = vot + 1/2gt²
20 = 100t + 1/2(9.91) t²
4.9t² + 100 t -20 = 0 quadratic equation
t = 0.19 s
Total time = 0.19 + 20.4 = 20.6 s
