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3 years ago

When reading the printout from a laser printer, you are actually looking at an array of tiny dots.

Physics

1 answer:

solniwko [45]3 years ago

7 0

Answer:

The value is $y = 3.097 * 10^{-5} \ m$

Explanation:

From the question we are told that

The diameter of the pupil is $d_p = 4.2 \ mm = 4.2 *10^{-3} \ m$

The distance of the page from the eye $d = 29 \ cm = 0.29 \ m$

The wavelength is $\lambda = 500 \ nm = 500 *10^{-9} \ m$

The refractive index is $n_r = 1.36$

Generally the minimum separation of adjacent dots that can be resolved is mathematically represented as

$y = [ \frac{1.22 * \lambda }{d_p * n_r } ]* d$

$y = [ \frac{1.22 * 500 *10^{-9} }{4.2 *10^{-3} * 1.36} ]* 0.29$

$y = 3.097 * 10^{-5} \ m$

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Two 2.0 cm * 2.0 cm metal electrodes are spaced 1.0 mm apart and connected by wires to the terminals of a 9.0 V battery. a. What

NARA [144]

Answer: a) 31.86 *10^-12 C=31.86 pC; b) 18 V

Explanation: In order to explain this problem we have to consider the expression a parallel plates capacitor,which is given by:

C=Q/V where C is equal to C=εo*A/d where A and D are the area and the separation between the plates.

also we have

Q=C*V=ε(o*A/d)*V=(8.85*10^-12*0.02*0.02/1*10^-3)*9=31.86*10^-12 C=31.86pC

Then if the plates apart to a new spacing of 2.0 mm the new capacitance is equal

Cnew=εo*A/2*d so Cnew =Cinitial/2

then Cnew =Q/Vnew (Q is constant after disconnection to the battery)

Finally Vnew= Q/(Cinitial/2)= 2*(Q/Cinitial)= 2*Vinitial= 2*9=18V

5 0

3 years ago

A box of mass m is suspended by two ropes from a ceiling. if the ropes make the same angle with the vertical, what is the tensio

lilavasa [31]

The tension, T, in each rope is T= mg/2Sinθ

<h3>What is tension force?</h3>

Tension refers to the pulling force in a string which acts in an opposite direction to the force pulling on it.

The tension in each of the ropes are equal since they both make the same angle with the vertical.

Assume the angle the ropes make with the vertical are both θ.

Let the tension in each be T₁ and T₂

Also, T₁ = T₂ = T

T₁Sinθ + T₂Sinθ = mg

2TSinθ = mg

T = mg/2Sinθ

Therefore, the tension, T, in each rope is T = mg/2Sinθ

Learn more about tension at: brainly.com/question/14336853

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7 0

1 year ago

What are the independent and dependent variables if kinetic energy

FrozenT [24]

The independent is how long the ball goes and the dependant is the distance how far the ball goes.

3 0

3 years ago

Find the exponent A in the equation

hodyreva [135]

Start by swapping the variables in the equations with their units (leave A alone for now): $v=\frac{a^2t^A}{x} \Rightarrow \frac{L}{T} = \frac{ (\frac{L}{T^2})^2 T^A }{L}$

Multiply by L and square the fraction: $\frac{L^2}{T} = \frac{L^2}{T^4} T^A \Rightarrow \frac{L^2}{T} \div \frac{L^2}{T^4}=T^A$

Divide the fraction by multiplying by the reciprocal: $\frac{L^2}{T} \times \frac{T^4}{L^2} = T^A \Rightarrow T^3=T^A$

Therefore A=3

5 0

3 years ago

A crossbow is fired horizontally off a cliff with an initial velocity of 15 m/s. If the arrow takes 4s to hit the ground, what i

marysya [2.9K]

Answer:

<em>The range of the projectile is 60 m</em>

Explanation:

<u>Horizontal Motion</u>

When an object is thrown horizontally with a speed vo from a height h, it describes a curved path ruled exclusively by gravity until it eventually hits the ground.

The horizontal component of the velocity is always constant because no acceleration acts in that direction, thus:

$v_x=v_o$

The vertical component of the velocity changes in time because gravity makes the object fall at increasing speed given by:

$v_y=g.t$

The horizontal distance is calculated as a constant speed motion:

$x = v_x.t$

Knowing the crossbow is fired horizontally at vo=vx=15 m/s and it takes t=4 s to hit the ground, thus the range of the projectile is:

x = 15*4 = 60

The range of the projectile is 60 m

8 0

3 years ago