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gizmo_the_mogwai [7]
3 years ago
9

When reading the printout from a laser printer, you are actually looking at an array of tiny dots.

Physics
1 answer:
solniwko [45]3 years ago
7 0

Answer:

The value is y  = 3.097 * 10^{-5} \  m

Explanation:

From the question we are told that

The diameter of the pupil is d_p  =  4.2 \ mm  =  4.2 *10^{-3} \  m

The distance of the page from the eye d =  29 \  cm  =  0.29 \  m

The wavelength is \lambda  =  500 \ nm =  500 *10^{-9} \  m

The refractive index is n_r =  1.36

Generally the minimum separation of adjacent dots that can be resolved is mathematically represented as

y  = [ \frac{1.22 *  \lambda }{d_p * n_r } ]* d

         y  = [ \frac{1.22 *  500 *10^{-9} }{4.2 *10^{-3} * 1.36} ]* 0.29

         y  = 3.097 * 10^{-5} \  m

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densk [106]

Answer:

Explanation:

a). Find the graph attached for the motion.

b). If a shopper walk 5.4 m westwards then 7.8 m eastwards,

   Distance traveled by the shopper = Distance traveled in eastwards + Distance traveled westwards

                                                            = 5.4 + 7.8

                                                            = 13.2 m

c). Displacement of the shopper = Distance walked westwards - Distance traveled eastwards

                                                      = 5.4 - 7.8

                                                      = -2.4 m

Therefore, magnitude of the displacement of the shopper is = 2.4 m

And the direction of the displacement is eastwards.

8 0
3 years ago
A man pushes a 60.8 kg crate across a rough surface with an applied force of 125 N and at a CONSTANT SPEED.
Sedbober [7]

Answer: Colby we both dumb if we need brainly lol

Explanation:

8 0
3 years ago
(a) State and explain which of the arrangements would have the greater extension of spring(s). (b) Explain if there are any chan
swat32

Answer:
arrangement 2

Explanation:
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3 0
2 years ago
Read 2 more answers
Se lanza una pelota de béisbol desde la azotea de un edificio de 25 m de altura con velocidad inicial de magnitud 10 m/s y dirig
MissTica

Answer:

 v_f = 24.3 m / s

Explanation:

A) In this exercise there is no friction so energy is conserved.

Starting point. On the roof of the building

         Em₀ = K + U = ½ m v₀² + m g y₀

Final point. On the floor

         Em_f = K = ½ m v_f²

         Emo = Em_g

         ½ m v₀² + m g y₀ = ½ m v_f²

        v_f² = v₀² + 2 g y₀

         

let's calculate

        v_f = √(10² + 2 9.8 25)

        v_f = 24.3 m / s

6 0
3 years ago
a 10 kilogram steel ball is dropped from the top of a tower 100 meters high the kinetic energy of the ball just before it sttike
EleoNora [17]

Explanation:

If we assume negligible air resistance and heat loss, we can assume that all of the Gravitational potential energy of the ball will turn into Kinetic energy as it falls toward the ground.

Therefore our Kinetic energy = mgh = (10kg)(9.81N/kg)(100m) = 9,810J.

4 0
3 years ago
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