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umka21 [38]
3 years ago
15

A force of 50 N was necessary to lift a rock. A total of 150 J of work was done. How far was the rock lifted? ​

Physics
1 answer:
Kitty [74]3 years ago
7 0

Answer:

\boxed {\boxed {\sf 3 \ meters}}

Explanation:

Work is the product of force and distance.

W=F*d

We know the force to lift the rock was 50 Newtons. The work was 150 Joules.

  • 1 Joule is equal to 1 Newton meters.
  • We can convert the units to make the problem simpler later. The work is also 150 Newton meters.

W= 150 \ N*m \\F= 50 \ N

Substitute the values into the formula.

150 \ N*m= 50 \ N * d

We want to solve for distance, so we must isolate the variable. Divide both sides of the equation by 50 Newtons.

\frac{150 \ N*m}{50 \ N }=\frac{50 \ N * d}{50 \ N }

The Newtons will cancel out.

\frac{150 \ m }{50} =d \\3 \ m =d

The rock was lifted <u>3 meters.</u>

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When a body of mass 0.25 kg is attached to a vertical massless spring, it is extended 5.0 cm from its unstretched length of 4.0
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Answer:

d=0.165m

Explanation:

Given

m=0.25kg,x_{1}=5cm*\frac{1m}{100cm}=0.05m,x_{2}=4cm*\frac{1m}{100cm}=0.04m,v=2\frac{rev}{s}

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0.25kg*4\pi^2*r=49*(r-0.04m)

r=0.205m

total distance is

d=0.205-0.04=0.165m

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