Incomplete question as many data is missing.I have assumed value of charge and electric field.The complete question is here
A charge of 28 nC is placed in a uniform electric field that is directed vertically upward and that has a magnitude of 5.00×10⁴ V/m.
What work is done by the electric force when the charge moves a distance of 2.70 m at an angle of 45.0 degrees downward from the horizontal?
Answer:
Explanation:
Given data
Charge q=28 nC
Electric field E=5.00×10⁴ V/m.
Distance d=2.70 m
Angle α=45°
To find
Work done by electric force
Solution
Answer:
from the position of the center of the Sun
Explanation:
As we know that mass of Sun and Jupiter is given as
distance between Sun and Jupiter is given as
now let the position of Sun is origin and position of Jupiter is given at the position same as the distance between them
so we will have
from the position of the center of the Sun
Answer:
m = 9795.9 kg
Explanation:
v = 35 m/s
KE = 6,000,000 J
Plug those values into the following equation:
6,000,000 J = (1/2)(35^2)m
---> m = 9795.9 kg
Answer:
Explanation:
What problem says can be written mathematically as:
Where:
The problem itself it's really simple, we only need to replace the data provided in the previous equation, but first, let's convert the units of the velocity from cm/s to m/s because we have to work with the same units and working in meters is the most apropiate action, because is the base unit of length in the International System of Units:
Now, we can replace the data in the equation and find the time it will take the bird to travel 3.7 m:
Solving for t, multiplying by t both sides, and dividing by 0.52 both sides: