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Blizzard [7]
3 years ago
13

When the following reaction is completed and written in the form of a net ionic equation, which of the following elements will N

OT be present in the equation?
Pb(NO3)2(aq) + K2SO4(aq)

a. Pb
b. S
c. O
d. N
Chemistry
1 answer:
Alex Ar [27]3 years ago
4 0

Answer:

d. N

Explanation:

Chemical equation:

Pb(NO₃)₂(aq)  + K₂SO₄(aq)  →  PbSO₄(s) + KNO₃(aq)

Balanced Chemical equation:

Pb(NO₃)₂(aq)  + K₂SO₄(aq)  → PbSO₄(s) + 2KNO₃(aq)

Ionic equation:

Pb²⁺(aq) + 2NO₃⁻(aq)  + 2K⁺(aq) + SO₄²⁻(aq)  → PbSO₄(s) + 2K⁺(aq) + 2NO₃⁻(aq)

Net ionic equation:

Pb²⁺(aq) + SO₄²⁻(aq)  → PbSO₄(s)

The NO₃⁻(aq) and K⁺(aq)are spectator ions that's why these are not written in net ionic equation. The PbSO₄ can not be splitted into ions because it is present in solid form.

Spectator ions:

These ions are same in both side of chemical reaction. These ions are cancel out. Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.  

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3 years ago
What is the molar mass of a substance?
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7 0
4 years ago
A 5.0 L vessel has a total pressure of 5.0 atm. The partial pressure of the gases in the
Bingel [31]

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<h3>Partial pressure of gases</h3>

This is the individual pressure exacted by each gas in the containing vessel. This partial pressure of individual gases make up the total pressure.

Pt = P₁ + P₂ + P₃ + P₄

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Thus, the partial pressure of the remaining gas that was not measured is 0.8 atm.

Learn more about partial pressure of gases here: brainly.com/question/19813237

8 0
2 years ago
What will be the new volume of a 250 mL sample of gas at 300 K and 1 atm if heated to 350 K at 1 atm?
AlekseyPX

The   new volume of a 250  Ml   sample of gas at 300k  and  1atm  if  heated to 350 k  at  1 atm  is  291.67  Ml



<u>calculation</u>

This  is  solved  using  the  Charles  law formula  since the  pressure  is constant.

that is V1/T1 = V2/T2  where,

V1 =250 ml

T1=300  K

V2=?

T2= 350 k


by making V2 the subject   of  the formula  by  multiplying  both side by T2

V2= T2V1/T1

V2= (350 K x 250 ml) / 300K =291.67 Ml


5 0
4 years ago
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