Answer:
no
Step-by-step explanation:
√(2*10= √20= 4.47
2*√10= 6.32
Flour to sugar....u have 3 1/2 cups of flour and 1 1/4 cups of sugar (not sure if u mean brown or granulated...but either way, they are the same)...so ur ratio can be 3.5 cups to 1.25 cups.....or it can be 7/2 cups to 5/4 cups...depends on if u want it in decimals or fractions.
to compare the 2 quantities....um...3 1/2 cups flour > 1 1/4 cups sugar
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how many cups of flour do u need for each egg....
3 1/2 cups of flour.....and 2 eggs
(7/2) / 2 =
7/2 * 1/2 =
7/4 or 1 3/4.....so u need 1 3/4 cups of flour per egg <==
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I am having trouble reading ur rate table....but if 3 dozen (36 cookies) requires 2 teaspoons, then....
cookies : 6 12 18 24 30 36 180
vanilla : 1/3 2/3 1 1 1/3 1 2/3 2 10
the strategy used was a proportion : 36/2 = (number of cookies) / x...I just subbed in number of cookies and solved for x (number of teaspoons).
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How many cookies do u need to sell to earn at least 60% of 120 ? and 40% of 120 ?
so if this relates to ur other question....then u r selling ur cookies at 1.60 for 4 cookies.....that means 1.60/4 = 0.40 per cookie
60% of 120 = 0.60(120) = 72
0.40x > = 72
x > = 72/0.40
x > = 180.....u would have to sell at least 180 cookies
40% of 120 = 0.40(120) = 48
0.40x > = 48
x > = 48 / 0.40
x > = 120....u would need to sell at least 120 cookies
Answer:
A
Step-by-step explanation:
In order for the length of the pieces to be as great as possible, the number of pieces must be as small as possible. Jason can't keep the rope in one piece, that doesn't count as cutting the rope into pieces because he hasn't cut the rope. If there were 2 equal pieces, each piece would be 60 / 2 = 30 feet, and since 30 is an integer, the answer is 2.
Answer:
a) Q1= 144.10
Median = 150
Q3=155.90
b) The 99 percentile would be:
And represent a value who accumulate 99% of the values below
Step-by-step explanation:
Let X the random variable that represent the scores of a population, and for this case we know the distribution for X is given by:
Where and
Part a
Lets begin with the first quartile:
(a)
(b)
We can find the quantile in the normal standard distribution and we got z=-0.674.
And we can apply the z score formula and we got:
And if we solve for a we got
The median for this case is the mean
For the third quartile we find the quantile who accumulate 0.75 of the area below and we got z=0.674 and we got:
Part b
We can find the quantile in the normal standard distribution who accumulate 0.99 of the area below and we got z=2.33.
And we can apply the z score formula and we got:
And if we solve for a we got
And represent a value who accumulate 99% of the values below