Answer:
Lesson 3 Quiz ReturntoAssessmentList Part 1 of 4 - 4.0/ 8.0 Points Question 1 of ... in the balloon containing regular air D.Each balloon has an equal number of atoms. ... The purity of those pre-1982 pennies are really about 95% copper (5% zinc ... that had a mass of 3.11 grams, how many atoms of copper would you have?
Explanation:
Answer:
A. 0.2395 w/w %
B. 2394ppm
Explanation:
A. To find concentrationin percent by mass of the solution we need to calculate mass of glycerol and mass of water. The formula is:
Mass glycerol / Total mass * 100
<em>Mass glycerol:</em>
The solution is 2.6x10⁻²moles / L. As there is 1L of solution there are 2.6x10⁻² moles of glycerol. In mass (Using molar mass glycerol: 92.09g/mol):
2.6x10⁻² moles of glycerol * (92.09g / mol) = 2.394g glycerol
<em>Mass of water:</em>
998.9mL and density = 0.9982g/mL:
998.9mL * (0.9982g/mL) = 997.1g of water.
That means percent by mass is:
% by mass: 2.394g / (997.1g + 2.394g) * 100 = 0.2395 w/w %
B. Parts per million are mg of glycerol per L of solution. As in 1L there are 2.394g. In mg:
2.394g * (1000mg / 1g) = 2394mg:
Parts per million: 2394mg / L = 2394ppm
Answer:
A common characteristic of most Alkali Metals is their ability to displace H2(g) from water. This is represented by their large, negative electrode potentials. In this event, the Group 1 metal is oxidized to its metal ion and water is reduced to form hydrogen gas and hydroxide ions. The general reaction of an alkali metal (M) with H2O (l) is given in the following equation:2M(s)+2H2O(l)⟶2M+(aq)+2OH−(aq)+H2(g)(1)
Explanation:
Answer:
gibberish
Explanation:
its literaly nothing _#_$&_θГ[§θμθ_(;!&#\=&.·&:ГГ:¬¬&μ!¬´€
Answer:
Component P, because being supported by ample evidence is a characteristic of a theory.
Explanation:
Hypothesis do not explain phenomenon they are just educated guesses that can be put into work to see if they are true of false.
Scientific theory on other hand, is widely accepted and supported by large amount of evidence and useful for explaining scientific phenomenon.