I think its the mass that changes but im not sure
Answer:
A. Mg(OH)2
Explanation:
all oxides are insoluble except those of Group IA metals. most sulfides S2- are insoluble, with the exceptions of Group I, II (slightly soluble) metals and ammonium - NH4+
The molecule BH3 is trigonal planar, with B in the center and H in the three vertices. Ther are no free electrons. All the valence electrons are paired in and forming bonds.
There are four kind of intermolecular attractions: ionic, hydrogen bonds, polar and dispersion forces.
B and H have very similar electronegativities, Boron's electronegativity is 2.0 and Hydrogen's electronegativity is 2.0.
The basis of ionic compounds are ions and the basis of polar compounds are dipoles.
The very similar electronegativities means that B and H will not form either ions or dipoles. So, that discards the possibility of finding ionic or polar interactions.
Regarding, hydrogen bonds, that only happens when hydrogen bonds to O, N or F atoms. This is not the case, so you are sure that there are not hydrogen bonds.
When this is the case, the only intermolecular force is dispersion interaction, which present in all molecules.
Then, the answer is dispersion interaction.
Answer:
(c) an aqueous solution of CO2 exhibits dipole-dipole forces between solute and solvent
Explanation:
Co2 is a non-polar molecule.
It is actually shown to be O=C=O.
When dissolved in water to get aqueous solution.
Dipole on water molecule can induce dipole on CO2.
This entails that we should have dipole-induced dipole forces when we have a mixture or solvent and solute.
But the given statement states dipole dipole forces between solute and solvent.
Hence the statement is false.