Answer:
Explanation:
The de
velopment of airbags began with the idea for a system that would ... of deaths or serious injuries decrease when an airbag and seat belt are used, ... An airbag must be able to deploy in a matter of milliseconds from the initial ... as hard as stone-- not the protective cushion you would want to crash into! ... Reactants ...
In classifying salts as neutral, acidic, or basic, it is important to take note of the strength of the acids and bases that they come from. A strong acid and strong base produce a neutral salt. A weak acid and strong base produce a basic salt. A strong acid and weak base produce an acidic salt. So the answers must be:
KCl = neutral (from HCl and KOH)
NH4Br = acidic (from NH4 and HBr)
K2CO3 = basic (from KOH and H2CO3)
NaCN = basic (from NaOH and HCN)
LiClO = basic (from LiOH and HClO)
Answer:
Potassium (K) and Fluorine (F)
Explanation:
A salt is formed with a metal and non-metal element from the periodic table of elements. if you look at the online ptable.com the upper right hand corner of each element shows the valence electrons for each element, and how many are in each shell for that element. Fluorine (F) has 7 valence electrons in its outer most shell, which means there is room for 1 more electron since the second shell can hold a max of 8. Potassium(K) has 1 electron in its outer most shell- which means is can fill in the 1 space available that fluorine has in its outer most shell. Since Potassium(K) is a metal and Fluorine(F) is a non-metal they can form an ionic compound, salt.
Barium is in group 2A, it looses 2 electrons to form the calcium ion BA2, i’ll send a picture of some of my notes, hopefully it helps:))
Celsius to Kelvin conversion
formula
<span>The temperature T in
Kelvin (K) is equal to the temperature T in
degrees Celsius (°C) plus 273.15:</span>
T(K) <span>= T(°C) + 273.15</span>
So
to convert the boiling point of cyclopropane from degrees Celsius to kelvin:
T(K) <span>= T(°C) + 273.15</span>
T(K) <span>= -33 +
273.15</span>
T(K) <span>= 240.15 K</span>
<span> </span>
