PLEASE HELP ASAP Why is burning biomass better than burning oil or coal?

3. Calculate the atomic mass of oxygen if the three common isotopes of oxygen have masses

snow_tiger [21]

Answer:

15.999 amu

Explanation:

15.999 amu

Explanation:

From the question given above, the following data were:

Isotope A:

Mass of A 15.995 amu

Abundance (A%) = 99.759%

Isotope B:

Mass of B = 16.995 amu

Abundance (B%) = 0.037%

Isotope C:

Mass of C = 17.999 amu

Abundance (C%) = 0.204%

Atomic mass of Oxygen =.?

The atomic mass of oxygen can be calculated by using the following formula:

Atomic mass = [(Mass of A × A%)/100] + [(Mass of B × B%)/100] + [(Mass of C × C%)/100]

Atomic mass = [(15.995 × 99.759)/100] + [(16.995 × 0.037)/100] + [(17.999 × 0.204)/100]

Atomic mass = 15.956 + 0.006 + 0.037

Atomic mass = 15.999 amu

Therefore, the atomic mass of oxygen is 15.999 amu

5 0

3 years ago

How many of the following molecules have sp2 hybridization on the central atom? hcn so2 ocl2 xecl2.

GrogVix [38]

Only one molecule have sp2 hybridization on central atom and that is SO₂.

XeCl₂ have sp3d hybridization.

OCl₂ have sp3 hybridization.

HCN have sp hybridization.

Hybridization is defined as the concept of mixing two atomic orbitals to give rise to a new type of hybridized orbitals.

Hybridization intermixing usually results in the formation of hybrid orbitals having entirely different energies, shapes, etc.

Learn more about hybridization here:- brainly.com/question/22765530

#SPJ4

7 0

1 year ago

A 21.82 gram sample of an organic compound containing C, H and O is analyzed by combustion analysis and 21.33 grams of CO2 and 4

morpeh [17]

Answer: The molecular formula for the given organic compound is $C_2H_2O_4$

Explanation:

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

$C_xH_yO_z+O_2\rightarrow CO_2+H_2O$

where, 'x', 'y' and 'z' are the subscripts of Carbon, hydrogen and oxygen respectively.

We are given:

Mass of $CO_2=21.33g$

Mass of $H_2O=4.366g$

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

For calculating the mass of carbon:

In 44g of carbon dioxide, 12 g of carbon is contained.

So, in 21.33 g of carbon dioxide, $\frac{12}{44}\times 21.33=5.82g$ of carbon will be contained.

For calculating the mass of hydrogen:

In 18g of water, 2 g of hydrogen is contained.

So, in 4.366 g of water, $\frac{2}{18}\times 4.366=0.485g$ of hydrogen will be contained.

Mass of oxygen in the compound = (21.82) - (5.82 + 0.485) = 15.515 g

To formulate the empirical formula, we need to follow some steps:

Step 1: Converting the given masses into moles.

Moles of Carbon = $\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{5.82g}{12g/mole}=0.485moles$

Moles of Hydrogen = $\frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.485g}{1g/mole}=0.485moles$

Moles of Oxygen = $\frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{15.515g}{16g/mole}=0.969moles$

Step 2: Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.485 moles.

For Carbon = $\frac{0.485}{0.485}=1$

For Hydrogen = $\frac{0.485}{0.485}=1$

For Oxygen = $\frac{0.969}{0.485}=1.99\approx 2$

Step 3: Taking the mole ratio as their subscripts.

The ratio of C : H : O = 1 : 1 : 2

Hence, the empirical formula for the given compound is $C_1H_{1}O_2=CHO_2$

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is :

$n=\frac{\text{molecular mass}}{\text{empirical mass}}$

We are given:

Mass of molecular formula = 90.04 g/mol

Mass of empirical formula = 45 g/mol

Putting values in above equation, we get:

$n=\frac{90.04g/mol}{45g/mol}=2$

Multiplying this valency by the subscript of every element of empirical formula, we get:

$C_{(1\times 2)}H_{(1\times 2)}O_{(2\times 2)}=C_2H_2O_4$

Thus, the molecular formula for the given organic compound is $C_2H_2O_4$

4 0

4 years ago

When comparing the successive ionization energies of an element, an unusually big increase in ionization energy is seen when ___

Murljashka [212]

Answer:

The first valence electron is removed.

Explanation:

Ionization energy is the energy that is needed to tear out the last electron of an atom in its ground state or gaseous state.

A(g) + IE ----> A+(g) + 1e-

When we talk about starting an electron we refer to the last valence electron, since it is the one that is furthest from the atomic nucleus, the one that does not feel attracted. As the question asks us the opposite, the ionization energy is going to be extremely high, if the electron to be removed occupies the first valence layer, since it is totally attracted to the nucleus.

8 0

4 years ago

Which of the following shows a valid combustion reaction?

marta [7]

Answer: C2H4 + 3O2 → 2CO2 + 2H2O

Explanation:

2Al + 2O2 → 2AlO + O2 Not Balanced Properly: 2Al + O2 = 2AlO

C2H4 + 3O2 → 2CO2 + 2H2O Looks Good

2CH4 + O2 → 2CO + 4H2 Not Correct: CO should be CO2

Ca + O2 → CaOH Not Balanced and No source for the H

3 0

2 years ago

Read 2 more answers