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Bezzdna [24]
3 years ago
12

Convert the boiling point of cyclopropane at standard pressure to kelvins

Chemistry
1 answer:
Olenka [21]3 years ago
3 0
Celsius to Kelvin conversion formula

<span>The temperature T in Kelvin (K) is equal to the temperature T in degrees Celsius (°C) plus 273.15:</span>

T(K) <span>= T(°C) + 273.15</span>

 

So to convert the boiling point of cyclopropane from degrees Celsius to kelvin:

T(K) <span>= T(°C) + 273.15</span>

T(K) <span>= -33 + 273.15</span>

T(K) <span>= 240.15 K</span>

<span> </span>
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100 Points and Brainliest
Vedmedyk [2.9K]

Answer:

100 g

Explanation:

We know the concentration is 200 g/L.

Convert 500mL to L: 500mL/1000mL = 0.5 L

Now, multiply this by 200 to cancel out the L units and get grams:

200 g/L * 0.5 L = 100 g

Thus, the answer is 100 grams.

Hope this helps!

5 0
3 years ago
A sample of gold (Au) has a mass of 35.12 g.
rjkz [21]

Answer:

a) 0.1783 mol

b) 1.07*10^23 atoms

Explanation:

Step 1: Data given

Mass of gold (Au) = 35.12 grams

Molar mass of gold (Au)  = 196.97 g/mol

Number of Avogadro = 6.022 *10^23 /mol

Step 2: Calculate number of moles gold

Number of moles = Mass of gold / molar mass of golf

Number of moles = 35.12 grams / 196.97 g/mol

Number of moles =  0.1783 moles

Step 3: Calculate number of atoms of gold

Number of atoms = number of moles * Number of Avogadro

Number of atoms = 0.1783 * 6.022 *10^23/ mol

Number of atoms = 1.07*10^23 atoms

7 0
4 years ago
calculate the water potential of a solution of 0.15m sucrose. the solution is at standard temperature.
Mrac [35]

Answer:

The water potential of a solution of 0.15 M sucrose solution is -3.406 bar.

Explanation:

Water potential = Pressure potential + solute potential

P_w=P_p+P_s

P_w=P_p+(-iCRT)

We have :

C = 0.15 M, T = 273.15 K

i = 1

The water potential of a solution of 0.15 m sucrose= P_w

P_p=0 bar (At standard temperature)

P_s=-iCRT=-\times 1\times 8.314\times 10^{-2}bar L/mol K\times 273.15 K=-3.406 bar

P_w=0 bar+(-3.406 ) bar

The water potential of a solution of 0.15 M sucrose solution is -3.406 bar.

7 0
3 years ago
calculate the ph of the resulting solution if 17.0 ml of 0.170 m hcl(aq) is added to 22.0 ml of 0.170 m naoh(aq).
Natalka [10]

The pH of the finsl solution is equal to <u>2.93</u>

Concentration is the abundance of a constituent divided by way of the overall volume of an aggregate. several sorts of mathematical descriptions may be outstanding: mass concentration, molar concentration, variety concentration, and extent awareness.

C₁ = 0.170 m

V₁ = 17 ml = 0.017 L

C₂ = 0.170 M

V₂ = 22 ml = 0.022 L

C₁V₁ =C₂V₂

0.170× 0.017 L = 2.89 × 10⁻³  ------------- HCl

0.170× 0.022 L = 3.74 × 10⁻³  ------------ NaOH

⇒ 3.74 × 10⁻³  -  2.89 × 10⁻³ = 0.85 × 10⁻³

⇒ 3 + log 0.85

⇒ 3 + -0.07

⇒ pH = <u>2.93</u>

The concentration of an solution is a degree of the amount of solute that has been dissolved in a given amount of solvent or solution. A focused solution is one which has a rather huge amount of dissolved solute.

Learn more about concentration here:-brainly.com/question/26255204

#SPJ4

5 0
1 year ago
Name the type of bond between atoms in ammonia molecule. Give a reason for your answer
Likurg_2 [28]

Answer:

Covalent bonds are formed when electrons are shared between elements that are nonmetals. The ammonium ion, NH+4 , would have covalent bonds because both nitrogen and hydrogen are nonmetals. ... The rest of the bonds all contain electrons from both hydrogen and nitrogen, so they would be considered ordinary covalent bonds.

6 0
3 years ago
Read 2 more answers
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