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Answer:
56.9 mmoles of acetate are required in this buffer
Explanation:
To solve this, we can think in the Henderson Hasselbach equation:
pH = pKa + log ([CH₃COO⁻] / [CH₃COOH])
To make the buffer we know:
CH₃COOH + H₂O ⇄ CH₃COO⁻ + H₃O⁺ Ka
We know that Ka from acetic acid is: 1.8×10⁻⁵
pKa = - log Ka
pKa = 4.74
We replace data:
5.5 = 4.74 + log ([acetate] / 10 mmol)
5.5 - 4.74 = log ([acetate] / 10 mmol)
0.755 = log ([acetate] / 10 mmol)
10⁰'⁷⁵⁵ = ([acetate] / 10 mmol)
5.69 = ([acetate] / 10 mmol)
5.69 . 10 = [acetate] → 56.9 mmoles
Tue answer is 13 hope this help
Answer:
NaHCO3 + HCl ——-> NaCl + H2O + CO2
Explanation:
A neutralization reaction is a chemical reaction between an alkali and an acid to give salt and water as the product.
In the case of carbonates and bicarbonates, an additional product is added. This additional product is carbon iv oxide.
Hence a neutralization reaction involving an acid and a carbonate or bicarbonate would yield water, carbon iv oxide and a salt as the product.
When brioschi reacts with hydrochloric acid, the products are sodium chloride, water and carbon iv oxide.
The equation of the reaction is shown below:
NaHCO3 + HCl ——> NaCl + H2O + CO2