Answer:
Explanation:
Given:
dI/dt = 6.21 A/s
n = N/l
= 100 turns/cm
= 100 turns/cm × 100 cm/1 m
Radius, r = 14.7 cm
= 0.147 m
Inductance, L = uo × n^2 × A × l
L/l = 4pi × 10^-7 × (100 × 100)^2 × pi × 0.147^2
= 8.53 H
Emf, E = L × dI/dt
E/l = L/l × dI/dt
= 8.53 × 6.21
= 52.98 V/m
=
Answer:
The acceleration of a 2 kg box acted on by a net force of 2 N is solved by using Newton’s second law of motion in the form acceleration = F_net / mass. Since the mass of the box is 2 kg and the net force is 2 N, the acceleration of the 2 kg box is 1 m/s^2.
Charge dQ on a shell thickness dr is given by
dQ = (charge density) × (surface area) × dr
dQ = ρ(r)4πr²dr
∫ dQ = ∫ (a/r)4πr²dr
∫ dQ = 4πa ∫ rdr
Q(r) = 2πar² - 2πa0²
Q = 2πar² (= total charge bound by a spherical surface of radius r)
Gauss's Law states:
(Flux out of surface) = (charge bound by surface)/ε۪
(Surface area of sphere) × E = Q/ε۪
4πr²E = 2πar²/ε۪
<span>E = a/2ε۪
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Answer: 20m/s.
Explanation:
Remember the second Newton's law:
F = a*m
This is:
The net force acting on an object is equal to the mass of the object times the acceleration of the object.
In this case, we have a force of 5N pushing the object to the right.
We also have a force of 5N pushing the object to the left.
These forces act on opposite directions.
Then the net force will be equal to the difference of these forces, this is:
F = 5N - 5N = 0N
Then the net force is 0N, then we have:
0N = m*a
0N/m = 0m/s^2 = a
This means that the acceleration of the object is 0, then the velocity of the object does not change.
This means that if the object was moving at a constant velocity of 20m/s, the velocity of the object will still be equal to 20m/s. (because the net force acting on the object is zero)
2) solution gets broken down to solute and solvent.
