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sdas [7]
3 years ago
5

Find the acceleration for a force of 2 N acting on 2 kg.

Physics
1 answer:
igomit [66]3 years ago
4 0

Answer:

The acceleration of a 2 kg box acted on by a net force of 2 N is solved by using Newton’s second law of motion in the form acceleration = F_net / mass. Since the mass of the box is 2 kg and the net force is 2 N, the acceleration of the 2 kg box is 1 m/s^2.

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Heather writes the equations below to represent two lines drawn on the coordinate plane. –6x + 18y = 0 4x – 12y = 20 After a
devlian [24]

Answer:

The system has no solution

Explanation:

You can check it graphically, the pair of equations represents two lines, if they never cross, or if they are parallel, the system of equations is inconsistent and has no solution.

I attached you two pictures in which you can see the graphical result.

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3 years ago
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A string is wrapped around a uniform disk of mass M = 1.2 kg and radius R = 0.07 m. (Recall that the moment of inertia of a unif
pentagon [3]

Explanation:

Given that,

Mass of disk = 1.2 kg

Radius = 0.07 m

Radius of rod = 0.11 m

Mass of small disk = 0.5 kg

Force = 29 N

Time t = 0.022 s

\theta=0.023\ m

Distance d= 0.039 m

(I). We need to calculate the speed of the apparatus

Using work energy theorem

W=\Delta K.E

Fd=\dfrac{1}{2}mv^2

v=\sqrt{\dfrac{2Fd}{M+4m}}

Where, m = total mass

v = velocity

F = force

d = distance

Put the value into the formula

v=\sqrt{\dfrac{2\times29\times0.039}{1.2+4\times0.5}}

v=0.840\ m/s

(b). We need to calculate the angular speed of the apparatus

Using formula of torque

\tau=I\alpha

F\times=(\dfrac{1}{2}MR^2+4mb^2)\alpha

29\times0.07=(\dfrac{1}{2}\times1.2\times0.07^2+4\times0.5\times0.11^2)\alpha

\alpha=\dfrac{29\times0.07}{0.02714}

\alpha=74.79\ rad/s^2

We need to calculate the angular speed of the apparatus

Using equation of angular motion

\omega=\omega_{0}+\alpha t

Put the value into the formula

\omega=0+74.79\times0.022

\omega=1.645\ rad/s

(c).  We need to calculate the angular speed of the apparatus

Using equation of angular motion

\omega_{0}^2=\omega^2+2\alpha t

Put the value into the formula

\omega_{0}^2=1.645^2+2\times74.79\times0.022

\omega=2.44\ rad/s

Hence, This is required equation.

7 0
3 years ago
An egg is drown at a wall and breaks. A second egg is thrown at the same velocity and collides with a bed sheet. The egg does no
alexdok [17]

Answer:

The first egg is thrown at a wall and breaks because it has no time to decelerate and it breaks.

While, when a second egg is thrown at wall with same velocity and collides with a bed sheet, it does not break because it get more time to decelerate  or collide with the wall.  It reduces the amount of force exerted on the egg and it does not break.

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3 years ago
A rigid container holds 0.30g of hydrogen gas.
Strike441 [17]

Answer:

Part A:    \mathbf{Q =94 \ J} to two significant figures

Part B:    \mathbf{Q =160  \ J} to two significant figures

Part C:    \mathbf{Q =220  \ J} to two significant figures

Explanation:

Given that :

mass of the hydrogen = 0.30 g

the molar mass of hydrogen gas molecule = 2 g/mol

we all know that:

number of moles = mass/molar mass

number of moles = 0.30 g /2 g/mol

number of moles = 0.15 mol

For low temperature between the range of 50 K to 100 K, the specific heat at constant volume for a diatomic gas molecule = C_v=\dfrac{3}{2}R

For Part A:

Q = mC_v\Delta T

Q= 0.15 \ mol (\dfrac{3}{2})(8.314 \ J/mole.K )(100-50)K

Q= 0.15 \times (\dfrac{3}{2}) \times (8.314 \ J )\times (50)

Q=93.5325 \ J

\mathbf{Q =94 \ J} to two significant figures

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Q = mC_v\Delta T

Q= 0.15 \ mol (\dfrac{5}{2})(8.314 \ J/mole.K )(300-250)K

Q= 0.15 \times (\dfrac{5}{2}) \times (8.314 \ J )\times (50)

Q=155.8875 \ J

\mathbf{Q =160  \ J} to two significant figures

Part C. For an extremely hot temperature, C_v=\dfrac{7}{2}R

Q = mC_v\Delta T

Q= 0.15 \ mol (\dfrac{7}{2})(8.314 \ J/mole.K )(2300-2250)K

Q= 0.15 \times (\dfrac{7}{2}) \times (8.314 \ J )\times (50)

Q=218.2425 \ J

\mathbf{Q =220  \ J} to two significant figures

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3 years ago
Over time Pangaea broke apart to form other continents.
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Answer:

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