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3 years ago

8

A race car has a mass of 710 kg. it starts from rest and travels 40.0 m in 3.0 s. the car is uniformly accelerated during the en

tire time. what is the net force exerted on it?

2 answers:

Oksanka [162]3 years ago

4 0

6300N is the answer i believe

goblinko [34]3 years ago

3 0

<span><span>6300 newtons.

If this was the appropriate answer make sure to mark as the brainliest!
-procklown</span></span>

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Answer:

a), b), d), and e) are correct.

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3 years ago

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A worker at the top of a 588-m-tall television transmitting tower accidentally drops a heavy tool. If air resistance is negligib

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The final velocity of the tool is 107.4 m/s

Explanation:

We can solve this problem by using the principle of conservation of energy.

In fact, if air resistance is negligible, the total mechanical energy of the tool is conserved during the fall, so we can write:

$K_i + U_i = K_f + U_f$

where

$K_i = 0$ is the kinetic energy of the tool at the top (zero since it is at rest)

$U_i = mgh$ is the gravitational potential energy of the tool at the top, where

m is the mass of the tool

g is the acceleration of gravity

h is the heigth of the tool

$K_f = \frac{1}{2}mv^2$ is the kinetic energy of the tool just before hitting the ground, where

v is the final speed of the tool

$U_f = 0$ is the gravitational potential energy of the tool at the bottom (zero since the height is zero)

Re-arranging the equation,

$mgh=\frac{1}{2}mv^2$

where we have

$g=9.8 m/s^2\\h=588 m$

And solving for v,

$v=\sqrt{2gh}=\sqrt{2(9.8)(588)}=107.4 m/s$

Learn more about kinetic energy and potential energy:

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3 years ago

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b,c

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4 years ago

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