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4 years ago

Find the sum of the first 21 terms of the sequence 5,9,13,17,21,...

Mathematics

1 answer:

alexandr1967 [171]4 years ago

8 0

Answer:

945

Step-by-step explanation:

The order of the sequence is to add 4, you keep on adding until you reach the exact number of term. When added, I got 945.

You might be interested in

First, rewrite 16/25 and 13/20 so that they have a common denominator.

Akimi4 [234]

Answer:

The answer to your question is 64/100 and 65/100

Step-by-step explanation:

Data

Common denominator of 16/25 and 13/20

Process

1.- Find the least common factor of 25 and 20.

25 20 2

25 10 2

25 5 5

5 1 5

L.C.F. = 2 x 2 x 5 x 5 = 100

2.- Convert each fraction to the denominator 100

100 / 25 = 4

16/25 = (16 x 4) / 100

= 64/100

100 / 20 = 5

13/20 = (13 x 5)/100

= 65/100

8 0

3 years ago

Read 2 more answers

The four-member math team at Pecanridge Middle School is chosen from the math club, which has three girls and five boys. How man

cestrela7 [59]

Answer:

$Total\ Selection = 30\ ways$

Step-by-step explanation:

Given

Girls = 3

Boys = 5

Required

How many ways can 2 boys and girls be chosen?

The keyword in the question is chosen;

This implies combination and will be calculated as thus;

$Selection =\ ^nC_r = \frac{n!}{(n-r)!r!}$

For Boys;

n = 5 and r = 2

$Selection =\ ^5C_2$

$Selection = \frac{5!}{(5-2)!2!}$

$Selection = \frac{5!}{3!2!}$

$Selection = \frac{5 * 4 * 3!}{3!*2 * 1}$

$Selection = \frac{20}{2}$

$Selection = 10$

For Girls;

n = 3 and r = 2

$Selection =\ ^3C_2$

$Selection = \frac{3!}{(3-2)!2!}$

$Selection = \frac{3!}{1!2!}$

$Selection = \frac{3 * 2!}{1 *2!}$

$Selection = \frac{3}{1}$

$Selection = 3$

Total Selection is calculated as thus;

$Total\ Selection = Boys\ Selection * Girls\ Selection$

$Total\ Selection = 10 * 3$

$Total\ Selection = 30\ ways$

5 0

4 years ago

The diagonal in a rectangle is 20 units long, and the angle between the diagonal and a side is 36º 42'.

mylen [45]

Side adjacent to the given angle: x
Diagonal=hypotenuse=20
cos (36° 42') =(side adjacent to angle 36° 42')/Hypotenuse
cos (36° 42')=x/20
Solving for x. Multiplying both sides of the equation by 20:
20 cos (36° 42')=20 (x/20)
20 cos (36° 42')=x
x=20 cos (36° 42')
x=20 (0.801775644)
x=16.03551288
x=16.04

Answer: Option D. 16.04

3 0

3 years ago

15-4i divided by 3i, it's algebra 2<br> .

Vanyuwa [196]

Answer:

13.6666666667

4 0

4 years ago

Please answer the attached question by selecting of the the given answers.

hichkok12 [17]

Answer:

Step-by-step explanation: